Given the square of x+x+1=0, find the value of the square of x to the 2006 power +x to the 2005 power +x to the 2004 power +.+x to the square+1 Answer me. For details I wouldn't understand if I was stupid. Given the square of x+x+1=0, find the value of the 2006 power of x+x and the 2005 power of x and the 2004 power of +.+x and the square of +x+1 Answer me. Details. I'm stupid. I might not understand. Given the square of x+x+1=0, find the value of the 2006 power of x+x and the 2005 power of x and the 2004 power of x+.+x and the square of x+x+1 Answer me. Details. I wouldn't understand if I was stupid.

Given the square of x+x+1=0, find the value of the square of x to the 2006 power +x to the 2005 power +x to the 2004 power +.+x to the square+1 Answer me. For details I wouldn't understand if I was stupid. Given the square of x+x+1=0, find the value of the 2006 power of x+x and the 2005 power of x and the 2004 power of +.+x and the square of +x+1 Answer me. Details. I'm stupid. I might not understand. Given the square of x+x+1=0, find the value of the 2006 power of x+x and the 2005 power of x and the 2004 power of x+.+x and the square of x+x+1 Answer me. Details. I wouldn't understand if I was stupid.

A total of 2007 items are grouped into groups of three
2006 Power of x +2005 power of x +…… +X squared +x+
=(2006 Power of x +2005 power of x +2004 power of x)+... +(Square of x +x+1)
= X to the 2004 power (x square+x+1)+ x to the 2001 power (x square+x+1)+... +(Square of x +x+1)
=0

Each group has a value of 0

Given x^2+x+1=0, find the value of x to the 2006 power +x to the 2005 power +x to the 2004 power +...+x^2+x+1.

X to the 2006 power +x to the 2005 power.+x to the 2nd power +x+1
= X^2004(x^2+x+1)+ x^2001(x^2+x+1).+x (x^2+x+1)+1
=0+0+.+0+1
=1