(2X to the third power-xyz)-2(x to the third power-y to the third power +xyz)+(xyz-2y to the third power), where x=1, y=2, z=-3.

(2X to the third power-xyz)-2(x to the third power-y to the third power +xyz)+(xyz-2y to the third power), where x=1, y=2, z=-3.

 

Given one-third xyz square times N = one-third x 4n+1 power y n+3 power z 5th power divided by 5x 2n+1 power y n-1 power, find N

One-third xyz-squared multiplication is known N=(5/3) x^(4n+1-2n-1)*y^(n+3-n+1)*z^5
=(5/3) X^(2n)*y^4z^5
So N=3(5/3)*x^(2n-1) y^(4-1)*z^(5-2)
I.e. N=5x^(2n-1)*y^3*z^3

Given one-third xyz-squared multiplication N=(5/3) x^(4n+1-2n-1)*y^(n+3-n+1)*z^5
=(5/3) X^(2n)*y^4z^5
So N=3(5/3)*x^(2n-1) y^(4-1)*z^(5-2)
I.e. N=5x^(2n-1)*y^3*z^3