Given that XYZ is a positive real number, and 3X (X power of 3)=4Y=6Z, prove 1/Z-1/X=1/2Y

3^X=4y=6z
So...
Y =3^x/4
Z =3^x/6
1/Z-1/2y =4/3^x-3/3^x =(4-3)/3^x =1/3^x =1/x
So
1/Z-1/2y=1/x
I.e.
1/Z-1/x=1/2y
Get proof

Given that x, y, z are rational numbers, A=2x cubic-xyz, B=y cubic-z quadratic+xyz, C=-x cubic+2y quadratic-xyz, and (x+1 And the absolute value of the quadratic +(y-1)+z of (x+1)=0, find the value of A-[2B-3(C-A)].

Absolute value of quadratic +(y-1)+z of (x+1)=0
So x+1=0, y-1=0, z=0
So x=-1, y=1, z=0
So A=-2-0=-2
B=1-0+0=1
C=1+2-0=3
Original formula = A-2B+C-3A
=-2A-2B+C
=4-2+3
=5

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