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Multiply the X power of 2 by the Y power of 3 and multiply by the Z power of 111=1998 to obtain the value of (XYZ
2^X*3^y*111^z =1998
1998=2*3*3*111
Corresponding to the original formula
X=1, y=2, z=1
2^X*3^y*111^z =1998
1998=2*3*3*111
Corresponding formula
X=1, y=2, z=1
Given x power of 2× y power of 3=1998, where x, y, z are natural numbers, find the value of (xyz) to the 2008 power
Given (2^x)(3^y)=1998, where x, y, z are natural numbers, find the value of (xyz) to the 2008th power.
For this problem, z is a natural number, but there is no limit to what z is a natural number. Even if the value of x and y can be found first but no value of z is given, it is impossible to ask for the value of (xyz)^2008.
Ask the questioner to examine the subject again.
Given (2^x)(3^y)=1998, where x, y, z are natural numbers, find the value of (xyz) to the 2008th power.
This problem z is a natural number, but there is no limit to what z is a natural number, even if you can first find the value of x, y but not given the value of z, to ask for (xyz)^ xyz)^2008.
Ask the questioner to examine the subject again.
RELATED INFORMATIONS
- 1. It is known thatth power of 2 is 3 times the Yth power of 3 times the Zth power of 111=1998, where X, Y and Z are natural numbers, the value of 2008th power of 2008th power of 2008th power of Y of X is obtained. It is known that the Xth power of 2 is 3 times the Yth power of 3 times the Zth power of 111=1998, where X, Y, Z are natural numbers, and the value of 2008th power of 2008th power of 2008th power of is obtained.
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