Given x-y=xy=3, if a, b are rational numbers a rational number and 2a's second power-2ab+b's second power +4a+4=0, then b+ab's (1+2)(1+2 To the second power)(1+2 to the fourth power)(1+2 to the eighth power)+2 to the fifteenth power. Give 0 point after finishing Give me 20 points after the answer, I'm sorry for the wrong number

Given x-y=xy=3, if a, b are rational numbers a rational number and 2a's second power-2ab+b's second power +4a+4=0, then b+ab's (1+2)(1+2 To the second power)(1+2 to the fourth power)(1+2 to the eighth power)+2 to the fifteenth power. Give 0 point after finishing Give me 20 points after the answer, I'm sorry for the wrong number

1) Square both sides of x-y=3 to obtain x2-2xy+y2=9, so that (x+y)2=x2+2xy+y2=(x2-2xy+y2)+4xy=9+12=212)2a of the square-2ab+b of the square+4a+4=0a2-2ab+b2+4a+4=0, a2-2ab+b2+a2...

If a, b is a rational number, and the second power of 2a-2ab+b+4a+4=0, then a+b= If a, b is a rational number, and the second power of 2a-2ab+b is +4a+4=0, then a+b=

2A-2ab+b+4a+4=0
A^2-2ab+b^2+a^2+4a+4=0
(A-b)^2+(a+2)^2=0
Because (a-b)^2>=0(a+2)^2>=0
So (a-b)^2=(a+2)^2=0
A-b=a+2=0
A=b=-2
A+b=-2-2=-4