A, b, c are known to be nonzero rational numbers, and the maximum value of the absolute value of a is m Is m, the minimum value is n, and find the value of m+n+1 power of 2012 A, b, c are known to be nonzero rational numbers, and the maximum value of the absolute value of a + b + b + c + c + abc + abc + abc is m Is m, the minimum value is n, find the value of m+n+1 power of 2012 A, b, c are known to be nonzero rational numbers, and the maximum value of the absolute value of a divided by a + b divided by b + c divided by c + abc divided by abc divided by abc is m Is m, the minimum value is n, find the value of m+n+1 power of 2012

A, b, c are known to be nonzero rational numbers, and the maximum value of the absolute value of a is m Is m, the minimum value is n, and find the value of m+n+1 power of 2012 A, b, c are known to be nonzero rational numbers, and the maximum value of the absolute value of a + b + b + c + c + abc + abc + abc is m Is m, the minimum value is n, find the value of m+n+1 power of 2012 A, b, c are known to be nonzero rational numbers, and the maximum value of the absolute value of a divided by a + b divided by b + c divided by c + abc divided by abc divided by abc is m Is m, the minimum value is n, find the value of m+n+1 power of 2012

I'll sort out the subject first.
X=a/|a b/|b c/|c abc/|abc|
M = max (x)=4(obviously, when abc is positive)
N=min (x)=-4(obviously, when abc is negative)
2012^(M+n+1)=2012^1=2012

A.b.c Nonzero rational number, find the value of ab/absolute value ab+bc/absolute value bc+ac/absolute value ac+abc/absolute value abc.

Ab/absolute ab+bc/absolute bc+ac/absolute ac+abc/absolute abc
1) A, b, c >0
Original formula=1+1+1+1=4
2) One of them