Two equals three!

Two equals three!

Two equals six thirds
6/3=2

How much is pi half equal to? It's just that PI in half is about equal to

π is about 3.1415926 divided by 2, which is about 1.5707963

Given the function f (x) = sin 3 / X cos 3 / x + sign 3 times cos 3 / 3 x, find the coordinates of the image symmetry center Given the function f (x) = SIN3 / X cos 3 / x + sign change 3 times cos 3 / 3 x, find the coordinates of image symmetry center

f(x)=[sin(2x/3)]/2+√3(1+cos2x/3)/2
=sin(2x/3+60°)+√3/2
∵ the symmetry center of SiNx is (K180 ° 0),
∴2x/3+60°=k180°,
∴x=k270°-90°,
 symmetric center coordinate (k270 ° - 90 ° 0)

Known vector a = (cos3 ′ 5 π, SIN3 ′ 5 π), B = = (cos3 ′ x, - SIN3 ′ x), X ∈ [0.2 ′ π]

(x) = cos (2x - π / 3) + 2Sin (x - π / 3) + 2Sin (x + π / 4) sin (x + π / 4) = cos2xcos π / 3 + 3 + sin2xsin π / 3 + 2Sin (x + π / 4) cos (x + π / 4) cos (x + π / 4) = 1 / 2cos 2x + root 3 / 2sin2x + sin (2x + π + 2 (2x + π / 2) = 3 / 2cos2x + root 3 / 2sin22x = root 3 (1 / 2sin22x + root 3 / 2cos2x) = root 3 (sin2x + root 3 / 2cos2x) = root 3 (sin2xcos π π π π π π π π π π π (2x/ 3 + cos2xsin

It is known that the rightward arrow on OA = (x in SIN3, X in root 3cos 3), rightward arrow on ob = (x in cos3, X in cos3) (x belongs to R), f (x) = OA It is known that the rightward arrow on OA = (x in SIN3, X in root 3cos 3), rightward arrow on ob = (x in cos3, X in cos3) (x belongs to R), f (x) = rightward arrow on OA multiplied by rightward arrow of ob, if x belongs to (0,3-th), find the value range of function f (x)

F (x) = sin (x / 3) cos (x / 3) + √ 3 [cos (x / 3)] ^ 2 = sin (2x / 3 + π / 3) + (√ 3) / 2
0, x = 0
The maximum value of sin (2x / 3 + π / 3) can be taken as 1
The value range of F (x) (√ 3, 1 + (√ 3 / 2)]

Is cos3 equal to cos (- 3)? Why?

Because cosine function is even function, it is symmetric about y axis. So cosx = cos (- x) is always true

Simplification: SIN3 α sinα-cos3α cosα= ___ .

The original formula = sin α Cos2 α + cos α sin2 α
sinα-cosαcos2α-sinαsin2α
cosα=cos2α+2cos2α-cos2α+2sin2α=2．
So the answer is: 2

If the final edge of angle a passes through the point (SIN3, - cos3), then the radian number of angle a is

π / 20, the final edge is in the first quadrant
The radian number of angle a is arctan [(- cos3) / SIN3] = arctan (- 1 / tan3)
=arctan[1/tan(π-3)]
=π/2-(π-3)
=3-π/2

If α∈ (0,2 π) is known, and its final edge intersects with the unit circle at point P (- SIN3, cos3), what is the radian number of angle α?

(-sin3)^2+(cos3)^2=1
sina=y/r=cos3/1=cos3=sin(π/2-3)
a=π/2-3+2kπ
α∈(0,2π)
a=5/2π-3

The degree of the angle a of the final edge passing through the point (SIN3, - cos3)?

π/20
In the first quadrant
tana=-cos3/sin3
=-cot3
=tan(3-π/2)
So a = 3 - π / 2