The least common multiple of 4.56 What is the least common multiple of 456

The least common multiple of 4.56 What is the least common multiple of 456

4 = 2 * 2, 5 = 1 * 5, 6 = 2 * 3, 4 and 6 have a common divisor 2, so only one can be taken, 2 * 2 * 5 * 3 = 60. The second kind of 4, 5, 6 first calculates the least common multiple of 4 and 5, which is 20, and then calculates the least common multiple of 20 and 6, which is 120. Because 20 and 6 have the same prime number 2, 120 divided by 2 is equal to 60

2. What are the least common multiples of 4, 5 and 6?

2. The least common multiple of 4, 5 and 6 is 60

How to find the least common multiple of 4,5,6?

Let's first express three numbers as the product of prime numbers
The second power of 4 = 2x2 = 2
The first power of 5 = 5
The first power of 6 = 2x3 = 2 and the first power of x3
Multiply the highest power of each prime number to get the least common multiple
Then the second power of 2 is x5x3 = 60

The least common multiple of 6.8.12.9

Thirty-six

The least common multiple of 2,4,6,8,12

24, because 2 times 12, two 24, 4 times 6, two 24, and 24 A kind of 8 2 3

How to calculate the least common multiple of 1 / 8 1 / 6 1 / 12,

The least common multiple of 1 / 4 and 1 / 8 is 1 / 4 (2 / 8)
The least common multiple of 1 / 6 and 1 / 12 is 1 / 6 (2 / 12)
Finally, it is found that the least common multiple of 1 / 4 (3 / 12) and 1 / 6 (2 / 12) is 1 / 2 (6 / 12)
The results were 1 / 2

It is known that cos (π / 6 - θ) = a (| a)|

cos(π/6-θ)=a
cos(5π/6+θ)
=-cos(π-5π/6-θ)
=-cos(π/6-θ)
=-a
sin(2π/3-θ)
=sin(π-2π/3+θ)
=sin(π/3+θ)
=cos(π/2-π/3-θ)
=cos(π/6-θ)
=a

Given cos (π / 6 - θ) = a (| a | ≤ 1), find the values of COS (5 π / 6 + θ) and sin (2 π / 3 - θ)

Train of thought: the key point is to change the angle. In the first question, 5 schools / 6 can be written as faction - school / 6; in the second question, 2 schools / 3 should be written as Pai / 2 + Pai / 6, and then the induction formula should be used to solve the problem. Finally, the first question is - A and the second question is a

If sin (α / 2) = √ 3 / 3, then cos α

solution
cosa
=1-2sin²(a/2)
=1-2(√3/3)²
=1-2/3
=1/3

How to prove cos (3 π / 2 - α) = - sin α It is proved by s (α + β) or s (α - β),

Certificate:
Left = cos (3 π / 2) cosa + SIN3 π / 2sina
=0×cosa+(-1)sina
=-sina
=Right
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