The ratio of the hypotenuse of a right triangle to one of its right angles is 13:12, and the other is 15. Find the circumference of the triangle

The ratio of the hypotenuse of a right triangle to one of its right angles is 13:12, and the other is 15. Find the circumference of the triangle

Let the hypotenuse be 13X and a right angle edge 12x
Then the other right angle side is 5x
5x=15
X=3
The hypotenuse is 39. The right angle is 36
The circumference is 39 + 36 + 15 = 90

If △ ABC is a right triangle, the two right sides are 5 and 12 respectively, and there is a point in the triangle where the distance from D to each side is equal, then the distance is equal to（ A.2 B.3 C.4 D.5

First of all, the right triangle side length 5.12.13 is not difficult to calculate, it is the radius of the inscribed circle of the triangle

What is the maximum area of a right triangle whose sum is 12?

The right angles are a and B
a+b=12
Because a > 0, b > 0
So 12 = a + b > = 2 √ ab
√ab

The square of the hypotenuse of a right triangle is twice the product of two right angles. This triangle has an acute angle () A. 15° B. 30° C. 45° D. 60°

Let the two right sides of a right triangle be a and B, and the hypotenuse of a right triangle be c
According to the square of the hypotenuse is equal to twice of the product of two right angle sides, we get: 2Ab = C2; according to Pythagorean theorem, we get A2 + B2 = C2, so A2 + B2 = 2Ab,
That is, A2 + b2-2ab = 0, (a-b) 2 = 0
If a = B, then the triangle is an isosceles right triangle,
So the acute angle of the triangle is 45 degrees
Therefore, C

The square of the hypotenuse of a right triangle is twice the product of two right angles. This triangle has an acute angle () A. 15° B. 30° C. 45° D. 60°

Let the two right sides of a right triangle be a and B, and the hypotenuse of a right triangle be c
According to the square of the hypotenuse is equal to twice of the product of two right angle sides, we get: 2Ab = C2; according to Pythagorean theorem, we get A2 + B2 = C2, so A2 + B2 = 2Ab,
That is, A2 + b2-2ab = 0, (a-b) 2 = 0
If a = B, then the triangle is an isosceles right triangle,
So the acute angle of the triangle is 45 degrees
Therefore, C

The square of the hypotenuse of a right triangle is twice the product of two right angles. This triangle has an acute angle ()

Let C be a right angle, C ^ 2 = a ^ 2 + B ^ 2
C ^ 2 = 2Ab  a ^ 2 + B ^ 2 = 2Ab
A = B, triangle ABC is an isosceles right triangle
Obviously, the acute angle is 45 degrees

If the square of the hypotenuse of a right triangle is twice the product of two right angles, what is the acute angle in the triangle

Let the right angles be a and B, and the hypotenuse be c
a²＋b²=c²
2ab=c²
So a 2 + B 2 = 2Ab
（a-b）²=0
A=b
The acute angle is 45 ° and isosceles right triangle

For a right triangle, the length of the longer right angle side is 10 cm more than that of the short right angle side, and the length of the oblique side is 25 cm

If the length of a shorter right angle side is xcm, the length of the other right angle side is (2x + 10) cm
According to Pythagorean theorem, X2 + (2x + 10) 2 = 252
X 1 = 7, x, 2 = - 15
Then 2x + 10 = 24
Then the area of the right triangle is 1
2×7×24=84cm2．
So the area of this right triangle is 84 cm2

Calculate the area of a right triangle with a hypotenuse length of 17cm and a right angle side length of 25cm?

My friend, you seem to have made a mistake. In a right triangle, the hypotenuse is the longest, and the hypotenuse is 25. Therefore, the square of Pythagorean theorem 17 plus the square of x = 25, x = 4 is 21 under the root, so the area is 68 and 21 under the root

The ratio of the two right sides of a right triangle is 3:4, the length of the slanted side is 25cm, and the height on the inclined side is given

12cm
Let a right triangle ABC, AB: AC = 4:3, the angle ABC is a right angle, and H is an oblique perpendicular foot
AB:BC=AH:HB=4:3
So BH = 12cm