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Given the arc length and arc height, calculate the arc diameter? Arc length 2240mm, radian height 500mm. Please inform the formula and results
Let the angle corresponding to the arc length be a and the radius R
Then the angle a = 2240 / (2 * 3.14 * r)
R = RCOs (A / 2) + H (H is high radian)
a. It can be found by substituting h into the above formula
Formula of arc radian The distance between the two ends is 12 meters?
Height h = 1m, distance between two ends L = 12m?
The arc radius is r
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=1/2+12^2/(8*1)
=18.5 M
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((12/2)/18.5)
=37.85 degrees
=37.85*PI/180
=0.660595 radian
What is the simplest formula for finding the radius of an arc? How to find the radius of an arc when the chord length and height of the arc are known?
If the chord length is a and the height is h, then r = √ (A / 4 + H 2)
1m per second = how many kilometers per hour correct conversion process
1m/s=10^(-3)km/(1/3600h)=3.6km/h
How much volume is equal to a drum with an inner diameter of 9 m and a height of 1 m. how to convert it into a formula
V=πR^2*H
=π*9^2*1
=81π
=254.34m^3
How many tons of water flow is equal to 1 m 3 / h? How to convert 2 m 3 water? Do you have the formula General villa a few tons of water an hour more suitable for the flow. Kneel thank you!
The problem is missing. 1m3 / h water flow is 1 ton / h water flow. 2m3 water is 2 tons water. The density of water is 1000 kg / m3. 1 cubic meter of water is 1 ton, and the flow rate of 1 m3 / h water is 1 ton per hour
The water consumption of ordinary residential buildings is 3.5 tons, which can be calculated according to the pipe diameter DN25 and the flow rate of 2m / s
The villa is bigger. For the general villa, it is recommended to use 4 ~ 5 tons / hour!
Speed unit conversion: 1m / S = 3.6km/h How did you get it
You can count units as numbers
1m / S = 1m / 1s and 1m = 1 / 1000 km, 1s = 1 / 3600 H
So 1m / S = 1m / 1s = (1 / 1000km) / (1 / 3600 h) = 3.6km/h
If the number of radians of the center angle of a fan-shaped circle is 2 and the chord length of the sector arc is 2, then the area of the sector is () A. 1 sin21 B. 2 sin22 C. 1 cos21 D. 2 cos22
The radius of the fan is 1
sin1．
The area of the sector is: 1
2×2×1
sin21=1
sin21
So choose a
The chord length of the central angle of a circle of 1 radian is 2. Find the arc length of the central angle of the circle, the area of the sector and the area of the arch between the central angle of the circle
Draw the figure, let the chord AB = 2, and the angle of the center of the circle it is facing is ∠ AOB. Make OD ⊥ AB at d (o is the center of the circle)
In RT Δ oad, ad = rsin1 / 2 ∠ AOD, i.e. 1 = rsin1 / 2
∴r＝1/sin1/2
Arc length L = α r = 1 * 1 / (sin1 / 2) = 1 / (sin1 / 2)
The other two formulas can be used
If the chord length corresponding to the central angle of a circle of 2 radians is 2, then the value of the fan-shaped area sandwiched by the central angle of the circle is Such as the title
The radius is 1 / sin1, the arc length is 2 / sin1, and the area is 1 / 2 * (1 / sin1) * (2 / sin1) = 1 / (sin1 ^ 2)
RELATED INFORMATIONS
- 1. If the number of radians of the center angle of a fan-shaped circle is 2 and the chord length of the sector arc is 2, then the area of the sector is () A. 1 sin21 B. 2 sin22 C. 1 cos21 D. 2 cos22
- 2. Given that the center angle of the circle is 60 degrees and the arc length is 2 π cm, what is the radius length of the sector? With publicity, specific
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- 12. If the arc length of a sector is 20 π cm and the area is 240 π cm 3, what is the central angle of the sector? Who can explain it clearly,
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- 14. If the radius of the circle is 50cm, then the circumference of the arc corresponding to the central angle of 30 ° is______ .
- 15. If the length of an arc is 18.84cm, and the radius of this arc is 4cm, what degree is the central angle of the arc
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