If the area of a sector with a radius of 16 cm is equal to that of a circle with a radius of 8 cm, then the arc length of this sector is () with π reserved

If the area of a sector with a radius of 16 cm is equal to that of a circle with a radius of 8 cm, then the arc length of this sector is () with π reserved

Let the arc length be xcm,
(1/2)×16x=π8^2
The solution is x = 8 π
So the arc length of this sector is 8 π cm

The central angle of a fan-shaped circle is 60 degrees. The arc length of the central angle is 3.14 cm. What is the area of this sector? Clear and clear,

3.14 △ 60 / 360 = 18.84cm (i.e. the circumference of the whole circle)
18.84 △ 2 △ 3.14 = 3cm (radius of circle)
The fan area is: 3.14 x 3 x 3 x 60 / 360 = 4.71 square centimeters
Answer: 4.71 square centimeter
That's enough. Give me a score (^_ ^)
Note: 60 / 360 is a fraction, "/" is not a divisor, it is a fractional line

The radius of the sector is 2 cm and the center angle is 60 ° so what is the area of the sector?

2 × 2 × 3.14 × 60 △ 360 = 2.093 (square centimeter)

The circumference of fan-shaped AOB is 8 cm (1) If the area of the sector is 3cm2, find the size of the central angle of the circle; (2) Find the area of the sector and get the maximum value of the center angle and chord length ab

Let the radius of the sector AOB be r, the arc length L, and the center angle of the circle α (1). From the problem 2R + L = 812lr = 3, the solution is: r = 3L = 2 or r = 1L = 6

A fan with a center angle of 45 ° and a radius of 8 cm has a circumference of () cm

According to the formula of arc length: arc length of sector = (45 × π × 8) / 180 = 2 π
So perimeter = 8 + 8 + 2 π = 16 + 2 π

If the perimeter of the sector is 8cm and the area is 4cm2, then the radian number of the central angle of the sector is () A. 1 B. 3 Two C. 2 D. 3

Let the arc length of the sector be l and the radius r, so 2R + L = 8,1
2lr=4,
So l = 4, r = 2,
So the number of radians of the central angle of the sector is 4
2=2;
Therefore, C

It is known that the circumference of the sector AOB is 8 cm. (1) if the area of the sector is 3 square cm, find the size of its central angle

Let the radius be x and the arc length y
Then 2x + y = 8 (1)
1/2xy=3(2)
The solution is: x = 1, y = 6 or x = 3, y = 2
When x = 1, y = 6, because n π * 1 / 180 = 6, n = 1080 / π
When x = 3, y = 2, because n π * 3 / 180 = 2, n = 120 / π
That is, the center angle of the circle is 1080 / π or 120 / π degree
Hope to adopt!

If the perimeter of the sector is 8cm and the area is 4cm2, then the radian number of the central angle of the sector is () A. 1 B. 3 Two C. 2 D. 3

Let the arc length of the sector be l and the radius r, so 2R + L = 8,1
2lr=4,
So l = 4, r = 2,
So the number of radians of the central angle of the sector is 4
2=2;
Therefore, C

If the perimeter of the sector is 8cm and the area is 4cm2, then the radian number of the central angle of the sector is () A. 1 B. 3 Two C. 2 D. 3

Let the arc length of the sector be l and the radius r, so 2R + L = 8,1
2lr=4,
So l = 4, r = 2,
So the number of radians of the central angle of the sector is 4
2=2;
Therefore, C

Given that the circumference of the sector is 6cm and the area is 2cm, the arc degree of the center angle of the fan is Hurry! Get the right answer!

Let the center angle of the sector be a and the radius of the sector be r
Then: S = pi * R ^ 2 * A / (2 * PI) = a * R ^ 2 / 2 = 2
Perimeter = 2 * pi * r * A / (2 * PI) + 2 * r = R * a + 2 * r = 6
A*R^2/2=2
A*R+2*R=6
R*(A+2)=6
R=6/(A+2)
A*R^2/2=A*(6/(A+2))^2/2=2
18*A=2*(A+2)^2=2*(A^2+4*A+4)
9*A=A^2+4*A+4
A^2-5*A+4=0
(A-4)(A-1)=0
A = 1 radian or a = 4 radians
R = 6 / (a + 2) = 2cm or r = 6 / (a + 2) = 1cm