What is Tan (- A + 3 PI in 2)?

What is Tan (- A + 3 PI in 2)?

Tan (- A + 3 π / 2) = Tan (- A + 2 π - π / 2) = Tan (- A - π / 2) = - Tan (π / 2 + a) = COTA

If Tan (α + β) = 3, Tan (α - β) = 2, what is α equal to

tan2α= tan﹙α+β+α-β﹚=[ tan﹙α+β﹚+tan﹙α-β﹚]/[1- tan﹙α+β﹚tan﹙α-β﹚]
=[3+2]/[1-3×2]=-1

Who knows how many degrees Tan is equal to two thirds Urgent need

Press tan-1 2 / 3 on the calculator to get what the angle is

How many degrees is Tan equal to three parts of 2105

Arctan3 / 25 = you can look up the math table

It is known that cosa = 1 / 7, cos (a-b) = - 13 / 14, and 0

The first problem is: A is an acute angle, and cosa = 1 / 7,  Sina = √ [1 - (COSA) ^ 2] = √ (1-1 / 49) = 4 √ 3 / 7. Tana = Sina / cosa = (4 √ 3 / 7) / (1 / 7) = 4 √ 3

It is known that a belongs to (0, π / 4), β belongs to (0, π), and Tan (α - β) = 1 / 2, Tan β = - 1 / 7, Tan (2A - β) and angle 2A - β

Let a = 2 (α - β)
Tan2（α-β）= tana
=2tan（α-β）/1-tan2（α-β）
=1/(1-1/4)
=4/3
tan（2α-β）=tan（a+β）= tana+ tanβ/(1- tana*tanβ)
=4/3-1/7 / 1+4/21
=25/25
=1
Because a belongs to (0, π / 4), β belongs to (0, π) and Tan (α - β) = 1 / 2, Tan β = - 1 / 7
SO 2 α - β = - 3 π / 4

It is known that Tan (α - β) = 1 2，tanβ=-1 7, and α, β ∈ (0, π), find the values of Tan α and 2 α - β

tan α=tan[（α-β）+β]=tan(α−β)+tanβ1−tan(α−β)tanβ=12+(−17)1−12×(−17)=13，tan（2α-β）=tan[（α-β）+α]=tan(α−β)+tanα1−tan(α−β)tanα=12+131−12×13=1．∵α、β∈（0，π）...

It is known that Tan α = 1 / 3, Tan β = - 1 / 7, and 0

tanα=1/3
Then tan2 α = 2tan α / (1-tan ^ 2 α) = 2 / 3 * 9 / 8 = 3 / 4
And Tan β = - 1 / 7,
So tan (2 α - β) = (tan2 α - Tan β) / (1 + tan2 α Tan β) = (3 / 4 + 1 / 7) (1-3 / 28) = 25 / 25 = 1
And 0

Given that Tan α = 3 / 4, α is the third quadrant angle, find the value of COS (α - π / 4)

Sin α / cos α = 3 / 4, sin square α + cos square α = 1, we can get sin α = 3 / 5, cos α = 4 / 5
Cos (α - π / 4) = (sin α + cos α) / Radix 2 = (7 * Radix 2) / 10
Sorry, it's wrong

It is known that Tan α = 4 If α is the third quadrant angle, then cos α The value of 2 is () A. Five Five B. −2 Five Five C. ± Five Five D. ±2 Five Five

Because α is the third quadrant angle, that is 2K π + π < α < 2K π + 3
2 π, K ∈ Z, K π + 1
2π＜α
2＜kπ+3
4 π, K ∈ Z, so α
2 is the second or fourth quadrant angle
∵tanα＝4
3，
∴cosα=-3
5=2cos2α
α, S-1 was obtained
2=±
Five
5，
Therefore, C