(1) Sin six, Tan three =? (2) Sin-3 + cos-6 × Tan =?

(1) Sin six, Tan three =? (2) Sin-3 + cos-6 × Tan =?

1, 3.2 below the root sign, (3 + 1) / 2

If x belongs to the school of zero to sixths, compare the sizes of Tan (Tan x), Tan (COS x), Tan (SiN x) and prove

X belongs to the zero to sixth school, Tan x √ 3 / 2, sin X

Tan (- 13 π) is larger than Tan (- 17 fifths π)

First, minus 13 π is larger than - 17 fifths
Tan value increases with the increase of degree
So tan (- 13 π) is larger than Tan (- 17 fifths π)

Comparison size: Tan (- 9 π / 4) and Tan (- 17 π / 5)

tan(-9x/4)=tan(-2.5x)
tan(-17x/5)=tan(-3.4x)
So the first one is bigger than the second
I can't call Pai on my cell phone

Comparison size (1) cos508 degree______ cos144°，tan(−13π 4)______ tan(−17π 5)．

（1）∵cos508°=cos148°=-cos32°，cos144°=-cos36°，
cos32°＞cos36°＞0，∴-cos32°＜-cos36°，∴cos508°＜cos144°．
（2）∵tan（-13π
4）=tan（-π
4）=-tanπ
4，tan（-17π
5 ）=tan（-2π
5）=-tan2π
5，
tanπ
4＜tan2π
5，∴-tanπ
4＞-tan2π
Therefore, Tan is (- 5 π)
4）＞tan（-17π
5 ）．

Given that in a triangle, SINB = 4 / 13, Tan = 5 / 12, then the size of angle ABC It is the problem of golden sun (10) in senior three

Tan what = 5 / 12?

How many degrees is tan α = two thirds?

33.690067°
33°41′24.24〃

What does the square of Tan mean? What about the square 30 of Tan

Tan 2 α = (Tan α) 2 is not tan (α 2)
Tan 2 30 degree = (Tan 30 degree) 2 = (√ 3 / 3) 2 = 1 / 3

The square of Tan π / 3 =?

The square of Tan π / 3 = (√ 3) 2 = 3

2tan15° The value of 1 − tan215 ° is equal to______ .

2tan15°
1−tan215°=tan30°=
Three
Three
So the answer is
Three
Three