Given that the complementary angle of an angle is complementary to its complementary angle, then the degree of this angle is______ .

Given that the complementary angle of an angle is complementary to its complementary angle, then the degree of this angle is______ .

If the degree of this angle is x, then its complementary angle is (90 ° - x) and its complementary angle is (180 ° - x),
According to the meaning of the title, (90 ° - x) + (180 ° - x) = 180 °,
X = 45 ° is obtained
So the answer is 45 degrees

Given that the complementary angle of an angle is 1 / 4 of its complementary angle, find the degree of this angle?

First of all, when we talk about the remainder, we will think that the two angles are complementary. If the required angle is x, then the quarter angle is 1 / 4x, then the sum of them is 90 degrees
Expressed by formula: x + 1 / 4x = 90 degrees
Let's solve x = 72 degrees, and that's where the quarter angle is 18 degrees
If you don't understand, just ask. I'd love to!

Cos (- π / 4) times Tan (- 5 π / 6) =?

-The fourth quadrant of the fourth quadrant is cos (- π / 4) = cos (π / 4) = cos (π / 4) = √ 2 / 2-5-5 π / 6 is the third quadrant Tan (- 5 π / 6) = Tan (π - 5 π / 6) = Tan (π / 6) = Tan (π / 6) = 3 / 3cos (π / 4) (π / 4) * Tan (- 5 π / 6) = cos (π (π / 4) * Tan (π - 5 π / 6) = cos (π / 4) * Tan (π / 4) * Tan (π / 6)) (π (- 5 π / 6) = Tan (- 5 π / 6) = √ 2 / 2 / 2 / 2 * √ 3 3 3 3 3 3 3 3) 3 / 3 (3 / 3 / 3/ 3 = √ 6 / 6

Sinπ/3Tanπ/3+tanπ/6COSπ/6－Tanπ/4COSπ/2

Sinπ/3Tanπ/3+tanπ/6COSπ/6－Tanπ/4COSπ/2
=(root 3) / 2 * (root 3) + (root 3) / 3 * (root 3) / 2 - 1 * 0
=3/2 +1/2 -0
=2

High school mathematics problem solving: Tan (- 1560 degrees) cos (17 of 6), online and so on

Tan (- 1560 degrees) cos (17 of 6)
=Tan (1440-1560 degrees) cos (17 of 6-2 π)
=tan(-120)cos(5π/6)
=-√3*(-√3/2)
=3/2

Why is Tan (- 4 / 23) divided into Tan (6 schools + 4 / schools)?

tan(－23π/4)=tan[(－6π)＋(π/4)]=tan[π/4]=1
Because: Tan (K π + W) = tanw, it holds for K ∈ Z

If Tan α = - 1 and α∈ [0, π), then the value of α is equal to () A. π Three B. 2π Three C. 3π Four D. 5π Four

∵ we know that Tan α = - 1 and α ∈ [0, π), so the final edge of α is on the ray y = - x (x ≤ 0), so α = 3 π
4，
Therefore, C is selected

Tan (45 degrees - a) Tan (45 degrees + a) + Tan (2 π - a) * Tan (3 / 4 π + a)

tan(π/4-a)tan(π/4+a)+tan(2π-a)*tan(3π/4+a)
=cot(π/4+a)tan(π/4+a)+(-tana)*(tana-1)/(tana+1)
=1-(tan²a-tana)/(tana+1)
=(-tan²a+2tana+1)/(tana+1)

Tan 165 degree evaluation As the title

Tan165 = - tan15 = - (tan45-tan30) / (1 + tan45tan30) = - (3-root3) / (3 + root3)
Simplify yourself

Evaluation: sin21 / 4 π Tan (- 23 / 6 π) cos1500 degrees

sin21/4π tan(-23/6π) cos1500°
=sin5π/4tanπ/6cos60°
=-sinπ/4*√3/6
=-√2/2*√3/6=-√6/12