How many roots are equal to?

How many roots are equal to?

4.123105626……

What is the negative root 17 of 85

√17÷√85
=√（17÷85）
=√（1/5)
=(1/5)√5

Root 17 divide root 85 multiply root 5

Root 17 divide root 85 multiply root 5
=√17×√5÷√85
=√85÷√85
=1；
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Radix 17 △ Radix 85 =?

Radix 17 △ Radix 85
=Radical 17 / 85
=Radical (1 / 5)
=Radical (1 * 5 / 5 * 5)
=The root of 5

Observe the following equation: ① 2-2 / 5 = 2 / 5 under 2 times root number; 2) 3-3 / 10 under root number = 3 / 10 under 3 times root number; 3-4 / 17 under root number = 4 / 17 under 4 times root number The expression of n (n) above should reflect the law of nature

N-N / (n * n + 1) = n / (n * n + 1)

What is root 26, root 17, root 5, root 20?

Root 20 + root 5 + root 17 + root 26
=2√5+√5+√17+√26
=3√5+√17+√26
=3*2.236+4.123+5.099
=6.708+9.222
=15.93

Root number 2-2 / 5 = 2 root number 2 / 5, root number 3-3 / 10 = 3 root number 3 / 10, root number 4-4 / 17 = 4 root number 4 / 17,1 According to this law, if the radical A-8 / b = a radical 8 / b (a, B are positive integers), then a + B is a + B=

A = 8. B = 65

The simplest quadratic radical root 2a-b and 3a + 1 under the A-1 root sign are the same kind of quadratic radical to find the values of a and B

a-1=2 2a-b=3a+1
The solution is: a = 3 B = - 4

In triangle ABC, it is proved that Tan (A / 2) Tan (B / 2) + Tan (B / 2) Tan (C / 2) + Tan (C / 2) Tan (A / 2) = 1 RTRTRTRTRTRT

The original formula = Tan (A / 2) * + Tan (B / 2) * Tan (C / 2) = Tan (A / 2) * Tan * + Tan (B / 2) * Tan (C / 2) = Tan (A / 2) * cot (A / 2) * + Tan (B / 2) * Tan (C / 2) = 1. Application formula: Tana + tanb = Tan (a + b) * (1-tana * tanb), I will not type the brackets, but use ＜ > >

ABC is a triangle. It is proved that: [Tan (A / 2)] ^ 2 + [Tan (B / 2)] ^ 2 + [Tan (C / 2)] ^ 2 > = 1

∵ (a-b) ^ 2 ≥ 0, ᙽ (a ^ 2 + B ^ 2) / 2 ≥ ab. if and only if a = B, "=" holds
Similarly, (B-C) ^ 2 ≥ 0, (C-A) ^ 2 ≥ 0, ν (b ^ 2 + C ^ 2) / 2 ≥ BC, (C ^ 2 + A ^ 2) / 2 ≥ ca
If and only if B = C, C = a, "=" holds
If and only if a = b = C, "=" holds
That is, when a = b = C, a ^ 2 + B ^ 2 + C ^ 2 is the minimum
When [Tan (A / 2)] = [Tan (B / 2)] = [Tan (C / 2)]
[Tan (A / 2)] ^ 2 + [Tan (B / 2)] ^ 2 + [Tan (C / 2)] ^ 2 is the smallest
That is, when a / 2 = B / 2 = C / 2 = π / 3, the original formula is the smallest
When a / 2 = B / 2 = C / 2 = π / 3, [Tan (A / 2)] ^ 2 + [Tan (B / 2)] ^ 2 + [Tan (C / 2)] ^ 2 = 1
∴[tan(A/2)]^2+[tan(B/2)]^2+[tan(C/2)]^2>=1