An isosceles right triangle, the shortest side is 10 cm, two acute angles are 45 degrees, what is the area of the triangle?

An isosceles right triangle, the shortest side is 10 cm, two acute angles are 45 degrees, what is the area of the triangle?

If I understand correctly, the shortest side is the right angle side, because it is an isosceles right triangle, the shortest side is 10 cm, so the area is 10 times 10 times 0.5 = 50 square centimeter

In a right triangle, one of the acute angles is 50 degrees. What is the other angle?

40 degrees, so simple

In a right triangle, one acute angle is twice the other. How many degrees are these two acute angles? Ask to calculate try!

Right triangle, obviously one angle is right angle, three angles of triangle add = 180 degrees
The other two angles add up = 90 degrees
Let a small acute angle degree: X, another acute angle degree: 2x (because it is twice the small acute angle)
∴ x+2x=90
X = 30 degrees
2X = 60 degrees
So the smaller acute angle equals 30 degrees. The larger acute angle equals 60 degrees
Is that all right?

An isosceles right triangle has a 10 cm long hypotenuse and two acute angles are 45 degrees. Can you work out its area?

Let the right angle side be X
The square of (2x) is the square of 10
That is, the square of x = 25
Then x = 5
S=5*5*1\2=25\2

One acute angle in a right triangle is 45 degrees. What is the other acute angle?

180-90-45
=90-45
=45 (degrees)
Another acute angle is 45 degrees

Write the inverse proposition of the proposition "if a triangle is a right triangle, then the acute angle between the bisectors of its two acute angles is 45 °", and prove that this proposition is true

The inverse proposition is: if the acute angle between the bisectors of two angles of a triangle is 45 °, then the triangle is a right triangle. As shown in the figure, △ ABC, be is the angular bisector of ∠ ABC, intersecting AC with E, ad is the bisector of cab, crossing BC at d, be and ad intersecting at o point, and ∠ EOA = 45 °

An acute angle of a right triangle is 45 degrees. What is this right triangle called?

Isosceles right triangle
In addition to a right angle, there are two acute angles, both 45 degrees
So it's an isosceles triangle
Together, it is an isosceles right triangle

One acute angle of a right triangle is equal to 45 degrees, and the other is equal to______ This triangle is also called______ .

180°-90°-45°,
=90°-45°,
=45°;
So it's an isosceles right triangle
A: the other angle is 45 ° and this triangle is an isosceles right triangle;
So the answer is: 45 ° isosceles right angle

In order to prove the proposition "in a right triangle, at least one acute angle is not greater than 45 degrees", the first step is to assume that the conclusion is not tenable___ .

If there is at least one acute angle not greater than 45 ° in a right triangle, the first step is to assume that the proved conclusion is not true, that is, both acute angles are greater than 45 °
So the answer is: both acute angles are greater than 45 degrees

In an isosceles right triangle, if an angle is 45 degrees, what is its length and width Its height is 2M and its width is what?

In an isosceles right triangle, if an angle is 45 degrees, then its two right angles are equal, and the hypotenuse is 2 times the root of the right angle
[question added: its height is 2M and its width is
If the height on the bevel is 2 meters
Then the hypotenuse is 2 × 2 = 4
Two right angle sides are 2 pieces of sign 2