Pythagorean theorem in RT △ ABC ∠ C = 90 ° given a = 300, B = 400, then C =?

Pythagorean theorem in RT △ ABC ∠ C = 90 ° given a = 300, B = 400, then C =?

Five hundred

1. In the triangle ABC, if the angle c = 90 °, C = 25cm, a: B = 2:3, then the triangle ABC = () cm ^ 2 There are two more questions 2. If the lengths of the two right sides of a right triangle are a and B, and the line on the hypotenuse is h, then 1 / (a ^ 2) + 1 / (b ^ 2) = () 3. If the height on the hypotenuse of an isosceles right triangle is 1cm, then the circumference of the triangle is () Please write the process

1.a/b=2/3=tanA=sinA/cosA,
sinA=2cosA/3,
sin^2A+cos^2A=1,
cos^2A=9/13,
cosA=3√13/13,sinA=2√13/13.
sinA=a/25,
a=25*sinA=50√13/13.
b=75√13/13.
S triangle area = 1 / 2 * AB = 1875 / 13cm ^ 2
2.1/2*√(a^2+b^2)*h=1/2*a*b,
h^2*(a^2+b^2)=(ab)^2,
Then 1 / (a ^ 2) + 1 / (b ^ 2) = (1 / h ^ 2)
3. The length of bevel side is: 1 + 1 = 2,
The side length of a right angle side is: √ 2
Then the circumference of the triangle is 2 (√ 2 + 1)

In the RT triangle ABC, the angle c is equal to 90 ° and a, B and C are the three sides of the triangle. If a: B = 1:2 and C = 5, what is the area of the triangle ABC?

Let two right angles be x, 2x, x 2 + 4x 2 = 25, x = 5
Area of triangle ABC = 5 * 20 / 2 = 50

If BC + AC = 14cm, ab = 16cm, then the area of RT triangle ABC is?

According to Pythagorean theorem
BC² + AC² = AB² = 16²
BC+AC=14
(BC+AC)² = BC²+AC² + 2*AC*BC = 14²
16² + 2*AC*BC = 14²
2*AC*BC = 14² - 16² < 0
unsolvable
If the title is changed to ab = 10cm
Then 2 * ac * BC = 14? 10? 2 = 96
AC*BC = 48
Area s = 1 / 2 * ac * BC = 24 cm

In △ ABC, ∠ C = 90 °. If a = 5, B = 12, then C = How to do this Pythagorean theorem

According to Pythagorean theorem: A ^ 2 + B ^ 2 = C ^ 2
So: C = a ^ 2 + B ^ 2 = 169 = 13

In the triangle ABC, if a: B = 5:12, C = 26, then a =? B =?

Let a = 5x, B = 12x,
So (5x) ^ 2 + (12x) ^ 2 = 26 ^ 2
The solution
X=2
therefore
a=10
b=24

In the triangle ABC, ∠ C = 90 degrees, a = 5, B = 12, then C =? Thank you very much`

C=13
Square of a + square of B = square of C
5*5+12*12=13*13
So C = 13

In △ ABC, ∠ C = 90 °, C = 25, B = 15, then a = x^2+15^2=25^2 x^2=25^2-15^2 x^2=625-225 x^2=400 x^2=20 Can it be reversed x^2+25^2=15^2 x^2=15^2-25^2 x^2=225-625 x^2= -400 x^2= -20

may not
Because ∠ C = 90 ° C = 25
So C is the hypotenuse
Then x ^ 2 + 15 ^ 2 = 25 ^ 2
So x = 20

In the triangle ABC, ∠ C = 90 °, a: B = 5:12, C = 6.5, then the value of B is?

5,12,13 are a group of Pythagorean numbers
So B = 12 / 2 = 6

In the RT triangle ABC, ∠ C = 90 ° if B = 15, C = 17, find a emergency

Radical 514