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The cosine value of an isosceles triangle is root 2 / 2, waist length is 3, root 2. Find the area of this isosceles triangle
If this angle is a vertex angle, nine 2 / 2
The bottom angle is 9
The upper bottom of the trapezoid is equal to the waist perpendicular to the bottom, and the other waist length with an angle of 45 degrees with the bottom is 4 pieces and 2 cm. Calculate the area of this trapezoid What I want is not the process, but the process of getting the answer
From the other end of the upper bottom, the height, the waist of 4 pieces of sign 2, and part of the bottom form an isosceles right angle triangle. The height is 4cm. From then on, it can be deduced that the upper bottom is 4cm and the lower bottom is 8cm. Thus, the trapezoid area is 24 square centimeter
The area of a trapezoid is 6, 5 minus 3, 10, and the lengths of the upper and lower edges are root 5 and 2 root 5 respectively. Find the height of this trapezoid
Let the height of this trapezoid be H
6 root sign 5 minus 3 root sign 10 = 1 / 2 (root number 5 + 2 root number 5) * h
6√5-3√10=3/2√5*h
2-√2=h/2
h=4-2√2
What is the area of the trapezoid when the angle between the waist and the bottom is 45 degrees
A right triangle is formed by making a vertical line downward from a point on the bottom
Because the waist length is 5 times the root sign 2, and the angle between the waist and the bottom is 45 degrees, it can be seen that this is an isosceles triangle with an oblique side of 5 times root 2. According to the Pythagorean theorem, the right angle side: 5
Trapezoid area: (4 + 5 + 4 + 5) × 5 × 1 / 2 = 45
The upper bottom of the trapezoid is equal to the waist perpendicular to the bottom, and the other waist length with an angle of 45 degrees from the bottom is 4 roots. 2. Calculate the area of the trapezoid
The upper base of the trapezoid is equal to the waist perpendicular to the base,
This is a right angled trapezoid,
The other waist length with an angle of 45 degrees from the bottom is 4 pieces and 2 pieces
The other waist is 4, the upper bottom is 4, and the lower bottom is 4 + 4 = 8
S=1/2（4+8）*4=24
The height of ABCD of isosceles trapezoid is 3cm, the base angle is 60 degrees, and the upper bottom is 3cm?
Tan60 = root 3, so the bottom consists of the length of the upper bottom and two 1cm, and the bottom is 5cm, so the area is 4 times the root 3
The two base lengths of isosceles trapezoid are 10 and 20 respectively, and one waist length is 89, then the diagonal length is______ .
As shown in the figure, make de ⊥ BC in E,
∵ ABCD is isosceles trapezoid, so CE = 1
2（20-10）=5，BE=15，
In the right angle, CDE = 8,
In the right angle △ BDE, BD is obtained by Pythagorean theorem=
82+152=17．
The circumference of the isosceles triangle is 2 + 2 times the root sign 3, and the height on the bottom edge is 1. Find the sin value of the base angle and the area of the isosceles triangle
Let the waist be x and the bottom edge be 2 + 2 √ 3-2x
x²=1+（1+√3-x）²
x=（3√3+1）/4
The bottom edge is = (√ 3 + 3) / 2
sin=1÷（3√3+1）/4=（6√-2）/13
Area = 1 / 2 × 1 × (√ 3 + 3) / 2 = (√ 3 + 3) / 4
If the difference between the two bases of an isosceles trapezoid is equal to one waist length, how many degrees is its lower base angle?
60 degrees
Let AD / / BC, ad < CB in trapezoidal ABCD
The parallel line De of waist AB is drawn through a vertex D of the upper bottom and intersected with a point E
Then abed is a parallelogram
So AB = de = CD,
CE = bc-be = BC-AD
Because the difference between the two bases of isosceles trapezoid is equal to one waist length
So CE = CD = De
So the triangle CDE is an equilateral triangle
So the bottom angle c is 60 degrees
If the bottom length of the isosceles trapezoid is equal to the sum of the waist length and the upper bottom, calculate the lower base angle As the title
60 degrees
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