It is known that the length of the upper and lower bottom of isosceles trapezoid is root 3 and root 12 respectively, and the height is root 6

It is known that the length of the upper and lower bottom of isosceles trapezoid is root 3 and root 12 respectively, and the height is root 6

Length of one waist = [6 ^ 2 + (0.5 * 3 ^ 0.5)] ^ 0.5 = 36.75 ^ 0.5
Length of diagonal = [6 ^ 2 + (1.5 * 3 ^ 0.5)] ^ 0.5

Given that the circumference of an isosceles trapezoid is 40 cm in circumference and 6 cm in height, and the waist length is equal to the median line, calculate the trapezoid area

It can be proved that any diagonal line is divided into two triangles, and the sum of the median lines of the two triangles is equal to the median line of the trapezoid, and the median line length of the triangle is equal to half of the length of the bottom edge. Thus, the median line of the trapezoid is 0.5 × (bottom + bottom). The circumference C = 40cm, and the two waist of isosceles trapezoid are equal

Isosceles trapezoid median line length 6 cm, waist length 4 cm, circumference is how many

Median line = (upper bottom + lower bottom) × 2
So: bottom + bottom = 6 × 2 = 12 cm
The circumference of this isosceles trapezoid is 12 + 4 + 4 = 20 cm

It is known that the waist length of isosceles trapezoid is equal to the median line, and the circumference is 3 cm, What is the median line of this trapezoid

Circumference = waist length + waist length + upper bottom + bottom = waist length + waist length + 2 * median line
=4 * median line = 3
So the median line is 0.75

The relationship between the area of isosceles trapezoid and waist In the isosceles trapezoid ABCD, the circumference is a and the two base angles are 60 degrees?

It should be a / 4
Make a double high line. If the length of the small line segment separated on both sides of the bottom is x, then the waist length is 2x, so the height is √ 3x
So s = (a-6x + 2x) √ 3x / 2
Therefore, when x = (0 + A / 4) / 2 = A / 8, the trapezoid area is the largest
So: the waist length is 2x = A / 4

It is known that the upper bottom of an isosceles trapezoid is 56 meters, the lower bottom is 69, 4 meters, and the waist length is 115. What is the area of the isosceles trapezoid

Find the height first: (69.4-56) × 2 = 6.7 115 × 115-6.7 × 6.7 = 13180.11, the square root is 114.8
According to the trapezoid area formula: (a + b) × h △ 2 (56 + 69.4) × 114.8 △ 2 = 7197.96
So the area is 7197.96 square meters, about 7198 square meters

An isosceles trapezoid, with an area of 1050 square meters and a height of 30 meters, of which one waist is 40 meters long? Please list the calculation method,

Let the top and bottom be x and the bottom be y
（x+y)*30/2 =1050
The solution is: x + y = 70
Because it is isosceles trapezoid, so both waist are equal to 40
So the circumference: x + y + 40 * 2 = 150

If the waist length of isosceles trapezoid is 5cm, the length of upper and lower bottom is 6cm and 12cm respectively, then its area is______ .

Be = 1
2（BC-AD）=3，
∴AE=
AB2−BE2=4，
The area of trapezoid = 1
2（AD+BC）×AE=36cm2．
So the answer is: 36cm2

The waist length of isometric trapezoid ABCD is 5, the length of upper and lower bottom is 6 and 12 respectively Eleven

Seeking height:
h=√{5^2-[(12-6)/2]^2}=4
Area of trapezoid = (6 + 12) * 4 / 2 = 36

It is known that the circumference of the isosceles trapezoid is 22.8 decimeters, the waist length is 6. The height is 4 decimeters? Complete, need equation

The sum of upper and lower bottom is 22.8-6.5x2 = 9.8
So the area of isosceles trapezoid is 9.8x4 △ 2 = 19.6 (square decimeter)