Given that the two right angles of a right triangle are 17 and 7 respectively, the degree of the greater acute angle is?

tan a=17/7
A = arctan (17 / 7) = 1.1801892830972098263557603762095 (radian)
=67.61986494804042617294901087668(°)
≈ 67.62(°)

The degree ratio of two acute angles of a right triangle is 7:8. What degree are the two acute angles?

90×7÷(7 + 8) = 42°
90×8÷(7 + 8) = 48°
So these two acute angles are 42 ° and 48 ° respectively

In RT △ ABC, the length of one right angle side is 8 cm, and the length of the center line on the inclined side is 5 cm, then the other right angle side is long______ .

∵ the length of the center line on the hypotenuse of a right triangle is 5 cm, and that of a right angle side is 8 cm,
The oblique side length is 2 × 5 = 10cm,
The length of the other right angle side=
102−82=6cm．
So the answer is: 6cm

Given that the circumference of a right triangle is 24 cm and the length of the center line on the hypotenuse is 5, find the two right sides of the right triangle

If one side length is x, then the other right angle side is 14-x, the square of (14-x) + the square of x = 10, x = 8, and the other right angle side is 6

A right triangle with an inner angle of 30 degrees has a center line of 5 on its hypotenuse and the shorter right angle is Let me know by 9:30. Thank you

5. The center line on the hypotenuse is equal to half of the hypotenuse, so the hypotenuse is 10, so the shortest right angle side is 5

In a right triangle, if the length of the two right sides is 12 and 5 respectively, then the length of the center line of the hypotenuse is () A. 26 B. 13 C. 30 D. 6.5

According to Pythagorean theorem, the hypotenuse C=
a2+b2=13，
∵ the center line on the hypotenuse of a right triangle is equal to half of the hypotenuse,
The length of the center line of the hypotenuse = 1
2×13=6.5．
Therefore, D

What is the length of the center line on the hypotenuse of a right triangle with two right angles of 12 and 16?

The Pythagorean theorem shows that the hypotenuse is 20, and the median line of the hypotenuse of a right triangle is half of the hypotenuse, so the median line is 20 / 2 = 10

Given that the center line on the hypotenuse of a right triangle is 5, and a right angle side is 3 / 4 of the other right angle side, calculate the area of the right triangle

Right triangle, it is easy to associate with Pythagorean theorem, and then in a right triangle, the central line of the hypotenuse is 1 / 2 of the hypotenuse, then the problem becomes very simple
Let a long side be a, a short side 3A / 4, and an oblique side 2 * 5, that is 10
Then, using the Pythagorean theorem:
a^2+（3a/4）^2=100
A = 8,
Triangle area: 8 * 6 * (1 / 2) = 24

If the lengths of the midlines on the two right sides of a right triangle are known to be 5 and 12 respectively, then the length of the center line on the hypotenuse of a right triangle is

If the lengths of the two right angles are 2a and 2b respectively, then:
The square of a + the square of (2b) = 25
The square of B + the square of (2a) = 144
Add the two formulas: the square of 5A + the square of 5B = 169
So, the square of a + the square of B = 169 / 5
So, the square of 4A + the square of 4B = 169 / 20
In other words, the square of (2a) + the square of (2b) = 169 / 20
Therefore, the length of the hypotenuse is 13 / (2 roots 5) = (13 roots 5) / 10

In a right triangle, the length of the center line on two right sides is 5 and 2 times the root sign Hurry up

Let two right angles be a, B
a²+b²/4=（2√10）²(1)
a²/4+b²=5²=25(2)
(1)-(2)a²-b²=20,a²=b²+20,(3)
(3) Substituting (1) B 2 = 16 (4)
(4) 3) a = 3
Hypotenuse = root 52 = 2 root 13

Given that the two right angles of a right triangle are 17 and 7 respectively, the degree of the greater acute angle is?