If the three sides of a right triangle are three continuous even numbers and the area is 48, what is the side length of the right triangle

If the three sides of a right triangle are three continuous even numbers and the area is 48, what is the side length of the right triangle

Let one side be a (even number) and the other two sides be A-2, a + 2. Because it is a right triangle, a ^ 2 + (A-2) ^ 2 = (a + 2) ^ 2 is a = 8
The three sides are 6, 8, 10,
The condition s = 48 is redundant

Given that the length of three sides of a right triangle is three continuous even numbers, the length of the three sides of the triangle is calculated. The unit of length is cm

Let the three sides of this right triangle be X-2, x, x + 2
（X-2)^2+X^2=(X+2)^2
2X^2-4x+4=x^2+4x+4
x^2-8x=0
Because x is the side length of a triangle, it can't be 0, so x = 8,
So, the three sides are: 6, 8, 10

The length of a right triangle is three consecutive integers. Find the length of three sides and its area

Let the length of three sides be three consecutive integers, that is, X-1, x, x + 1,
From the meaning of the title, (x-1) 2 + x2 = (x + 1) 2,
The solution is X1 = 0 (omitted), X2 = 4,
The length of the three sides is 3, 4, 5,
S△=1
2×3×4=6．

If the three sides of a right triangle are three consecutive even numbers, then the three numbers are There is another question Xiao Ming bought a mattress with a side length of 260 cm and a mattress with a thickness of 30 cm. The length of the door is 242 cm and the width is 100 cm. Can you take the mattress in? I'll add points... I'm very trustworthy

Let these three continuous even numbers be 2n-2; 2n; 2n + 2;
n> The integer of 1;
(2n-2)^2+(2n)^2=(2n+2)^2;
(n-1)^2+n^2=(n+1)^2;
n^2=4n;
N = 4; n = 0 (omitted)
The three consecutive even numbers are 4 * 2-2 = 6; 4 * 2 = 8.4 * 2 + 2 = 10;
Then these three numbers are 6, 8 and 10 respectively

If a right triangle has a right angle side of 12cm and an oblique side of 15cm, the area of the right triangle is ()

15^2-12^2=9^2
 9 * 12 = 108CM square

Using Pythagorean theorem to solve the area of a right triangle with a hypotenuse length of 17 cm and a right angle side of 15 cm

Another right angle side = root (17 ^ 2-15 ^ 2) = 8 area = 15 × 8 △ 2 = 60 square centimeter Pythagorean theorem: the square of a right angle side plus the square of another right angle side is equal to the square of the hypotenuse. That is, the square of 15 + the square of the other right angle side = 17, the other right angle side is 8. S = 1 / 2 * 8 * 15 = 60

Calculate the area of a right angle with an oblique edge of 17cm and a right angle side length of 15cm?

The square of 17 minus the square root of 15, then multiply the resulting number by 15 and divide by two

The length of the hypotenuse side is 17cm, and the area of a right triangle with a right angle side length of 8cm is______ cm2．

Let the other right angle side be X,
X is obtained from Pythagorean theorem=
172−82=
225=15，
The area of a right triangle is 1
2×8×15=60，
Therefore, the area of a right triangle is 60 cm2

As shown in the figure, in a square with side length C, there are four congruent right triangles with hypotenuse C and right angle sides a and B. can you use two methods to calculate the area of this square to explain the Pythagorean theorem? Try it

∵ s Square = 4 × 1
2Ab + (a-b) 2, s Square = C2,
∴4×1
2ab+（a-b）2=c2，
A 2 + B 2 = C 2

As shown in the figure, in a square with side length C, there are four congruent right triangles with hypotenuse C and right angle sides a and B. can you use two methods to calculate the area of this square to explain the Pythagorean theorem? Try it

∵ s Square = 4 × 1
2Ab + (a-b) 2, s Square = C2,
∴4×1
2ab+（a-b）2=c2，
A 2 + B 2 = C 2