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How to change the number 8 into 5 and add up to 1000
888+88+8+8+8=1000
Eight 8's make up five numbers. Five numbers add up to 1000. Can you do that? If you want to list the formula, how do you find that it's 888 + 88 + 8 + 8 + 8, which was given to me before 8 o'clock,
888+88+8+8+8=1000
Only the number 8 is used to make up five numbers. The sum of them is equal to 1000. What are the numbers?
1000/8=125,
You need 125 8's
888 has 111 8, 88 has 11 8, 8 has an 8
1000=888+88+8+8+8
How to make up five numbers with eight 8 and add up = 1000? ( )+( )+( )+( )+( )=1000
First of all, you should know that since there are five numbers, the tangent sum equals 1000, which means that the maximum of these five numbers can only be 888
Then, fill in 8 in each of the five blanks, and then 8 + 8 + 8 + 8 + 8 are left
If it's 88 + 88 + 88 + 8 + 8, it's obvious that it's quite different from 1000, so it can't be done
If it's 888 + 88 + 8 + 8 + 8, the answer is 1000
Only use the number 8 to make up five numbers and add them to make the equal number equal to 1000
888+88+8+8+8
Use the number 8 to make up five numbers, which add up to 1000. What are these five numbers
888+88+8+8+8
12345678 eight digits make up two three digits, so that their sum equals 1000?
24 groups
twelve million three hundred and forty-five thousand six hundred and seventy-eight
Let ABC + EFG = 1000
c+g=10 (2.8)(3.7)(4.6)
b+f=9 (1.8)(2.7)(3.6)(4.5)
a+e=9 (1.8)(2.7)(3.6)(4.5)
In this case, the sum of the two numbers is 1000
（2.8）（3.6）（4.5）
(3.7)(1.8)(4.5)
(4.6)(1.8)(2.7)
Example: take (4.6) (1.8) (2.7) and try to form 8 groups
214+786 216+874 286+714 124+876 284+716 126+874 824+176 826+174
Then: all of them have 3 * 8 = 24
Use eight cards to make two three digit numbers so that the sum of them is 1000. How many can you write?
342+658，432+568，143+857，413+587，124+876，214+786；348+652，438+562，147+853，417+583，126+874，216+784；358+642，468+532，157+843，487+513，176+824，286+714；352+648，462+538，153+847，483+517，17...
Eight identical numbers add up to 1000. What is this number
8 + 8 + 8 + 88 + 888 = 1000, that's it
Choose from the number cards 1, 2, 3, 4, 5, 6, 7, 8 to form two three digit numbers so that their sum is 1000?
Note that the sum of two three digit numbers must be equal to 10, and among these eight numbers, 2 + 8 = 3 + 7 = 4 + 6 = 10
In addition, the sum of the ten digits of two three digits and the sum of the hundred digits must be equal to 9, 1 + 8 = 2 + 7 = 3 + 6 = 4 + 5 = 9
Therefore, we can first determine a number of digits: take any group of 2 + 8, 3 + 7, 4 + 6, so that the sum of just two digits in the remaining number is equal to 9, so the following solution is obtained:
For the convenience of narration, ABC + def = 1000
To determine the value of C first, you can only take any number from 2, 3, 4, 6, 7, 8. There are C (6,1) methods. Once the value of C is determined, the value of F is also uniquely determined
Then determine the value of B. because the values of C and F have been determined, the two numbers that add up to C and f equal to 9 can not be used. In this way, the sum of the four numbers is 9, and B can be any one of the four numbers. That is, there are C (4,1) methods. Once the value of B is determined, the value of E is also uniquely determined
Finally, the value of a is determined. At this time, there are only two numbers left, and their sum is equal to 9. Therefore, the method of taking a is C (2,1), and D is also uniquely determined
Therefore, there are two triplets satisfying the condition: C (6,1) × C (4,1) × C (2,1) = 48 groups
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