1,2,3,4,5,6,7,8,9, these 9 numbers should not be repeated. Write a multiplication formula of four digits multiplied by one digit to get four digit numbers most urgent

1,2,3,4,5,6,7,8,9, these 9 numbers should not be repeated. Write a multiplication formula of four digits multiplied by one digit to get four digit numbers most urgent

The answer is:
1963×4=7852
1738×4=6952

Multiply 1, 2, 3, 4, 5, 6, 7, 8, 9 by one number to make the other four digits Numbers cannot be repeated

There are two groups of answers:
1738×5=6952
1963×4=7852

There's a six digit number, and when it's multiplied by 2, 3, 4, 5, 6, the result is still a six digit number, all numbers are the same The answer is 142857. Why? Please prove whether there are any numbers suitable for this condition

"7" is one of them. 1 / 7 = 0.142857 142857 142857... 2 / 7 = 0.285714 285714 285714... 3 / 7 = 0.428571 428571 428571... 4 / 7 = 0.571428 571428 571428... 5 / 7 = 0.714285 714285 714285... 6

Use 0,1,2 9 ten digits, which can form the number of three digits with repeated numbers

That's the number of all three digits
There are 999-100 + 1 = 900
What do not understand can continue to ask, at any time online

It is composed of 1-9. There must be 3 digits in 3 digits. How many combinations are there? Analysis: There are two kinds of combinations of 3-digit repetition: three numbers are the same, there are C19 = 9 kinds; only two numbers are the same, there are c19c18c13 = 216 kinds. Therefore, there are 9 + 216 = 225 kinds of combinations. I understand all the above, that is, how to explain C13. I don't quite understand. Please explain in detail, thank you

C19 takes one of nine numbers as two
C18 is one of the remaining eight numbers
C13 is to select a position from three digits to put that number
For example, C19 chooses 2 and C18 chooses 1. Then there are three possibilities of three digits, namely, C13

How many four digits can be made up of 1, 2, 3 and 4 without repeating numbers? Line them up. What number is 4123?

(1) 4 × 3 × 2 × 1 = 24,
(2) There are 3 × 2 × 1 = 6,
There are 3 × 2 × 1 = 6,
There are 3 × 2 × 1 = 6,
There are 3 × 2 × 1 = 6,
However, the number of four thousand bit operators (from small to large): 4123 4132 4213 4231 4312 4321,
6 × 3 + 1 = 19,
A: you can make up 24 four digit numbers without repeating numbers. Put them together. 4123 is the 19th number from small to large

The four digits of 1.2.3.4 can be used to make up many non repeating four digits. What is the sum of all these four digits? List the formula

In other words, the final result is 1000 * (1 + 2 + 3 + 4) * 6 + 1 * (1 + 2 + 3 + 4) * 6 + 1 * (1 + 2 + 3 + 4) * 6 + 1 * (1 + 2 + 3 + 4) * 6 + 1 * (1 + 2 + 3 + 4) * 6 = (1000 + 100 + 10 + 1) * (1 + 2 + 3 + 4) * 6 = 6666

Multiply the product of 1-8 eight digits into a hundred digit number, which is a thousand digit number. Eight numbers cannot be repeated

453 × 6 = 2718 or 582 × 3 = 1746

Use 1,2.3.4.5,6.7,8.9 to form an equation of four digits multiplied by one digit, which is equal to the other four digits. Each digit can only be used once

1963×4=7852
1738×4=6952

Five numbers, each containing 8. Let these five numbers add up to 1000. What are these five numbers Each number contains only one 8

If the sum of five 8's is 40, then if it is 0 in 10 bits, it needs to add 2 8's in 10 bits
The sum of two 8's is 16, and the 4 added by one digit is 20. Then if a hundred is 0, it needs an 8 in the hundreds
Just got into one, so I can write it out
8+8+8+88+888=1000