In the plane rectangular coordinate system, given the points a (- 4,0), B (2,0), the area of angle ABC is 12, and try to lack the coordinate characteristics of point C

In the plane rectangular coordinate system, given the points a (- 4,0), B (2,0), the area of angle ABC is 12, and try to lack the coordinate characteristics of point C

2-(-4)=6
twelve × 2÷6=4
C on a straight line 4 units away from the X axis, there are two such lines

In the plane rectangular coordinate system, the area of point a (- 5,0), point B (3,0) and △ ABC is 12. Try to determine the coordinate characteristics of point C Before Sunday

AB side length is 8, and the triangle area is calculated with ab as the bottom edge, s = 12 = 0.5 × eight × h. H is the distance from C to ab side (x axis), so h = 3, so the distance from C to X axis is 3, so the coordinate characteristics of point C are: arbitrary X coordinate, y coordinate is 3 or - 3

In the plane rectangular coordinate system, point a (- 4,0), point B (2,0) and the area of triangle ABC are known. 12. Try to determine the coordinates of point C

[0,4] and [0, - 4]

Point a (0, - 3), point B (0, - 4) and point C are on the x-axis. If the area of △ ABC is 15, find the coordinates of point C

AB = 1, let the abscissa of point C be x,
Then 1
two × one ×| x|=15，
The solution is x = ± 30
Therefore, the coordinates of point C are (30,0), (- 30,0)

In the plane rectangular coordinate system, point a (0, - 3), B (0,2) and point C are on the x-axis. If the area of triangle ABC is 15, find the coordinates of point C

Set the coordinates of C (x, 0)
　　 ½× ﹙2＋3﹚ ×| x|=15
　　x＝±6.
The coordinate of C is (6,0) or (- 6,0)

In the plane rectangular coordinate system, the three vertex coordinates of triangle ABC are known as a (- 3, - 2), B (0, - 5) and C (2,4), and the area of the triangle is calculated Please explain the solution steps and principle in detail. The following solution steps are not understood: make the origin point O. AC intersects the Y axis at point F. straight line AC: y = 6 / 5x + 8 / 5, when x = 0, y = 8 /... So the triangle ABC area = 33 / 5 + 99 / 10 = 33 / 2 = 16.5

Answer: you first draw triangle ABC in the plane rectangular coordinate system, and let AC intersect Y axis at point F, you will find that the area of triangle ABC is the sum of the area of triangle ABF and the area of triangle BFC. BF is the common bottom, BF = of + ob, so first find the analytical formula of straight line AC, and then find the length of of of (i.e. the vertical sitting of the intersection with y axis