Q: are two triangles of equal circumference the same size? It's best to explain why it's the same size or different

The area is not necessarily as large
For example:
Right triangle 3,4,5, area 3 * 4 / 2 = 6
Equilateral triangle 4,4,4, the area is 4 * 2 radical 3 / 2 = 4 radical 3

Triangle area perimeter

Triangle area: bottom * height / 2
Area of right triangle: multiply and divide two right sides to 2
Perimeter: sum of three sides

Triangle ratio 5:12:13, perimeter 60, area? Process

60 / (2 + 12 + 13) = 2 the two right angle sides are 2x5 = 12cm 2x12 = 24cm. The area of the right triangle = bottom x height / 2 = 12x24 / 2 = 144cm2
Can you solve your problem?

The ratio of three sides of a triangle is 5:12:13. If its circumference is 60cm, its area is () A. 100 B. 110 C. 120 D. 150

Let the three sides be 5x, 12x and 13X respectively,
Then 5x + 12x + 13X = 60,
∴x=2，
The three sides are 10cm, 24cm and 26cm respectively,
∵102+242=262，
The triangle is a right triangle,
∴S=10 × 24÷2=120cm2．
Therefore, C

The ratio of three sides of a triangle is 5:12:13, and its perimeter is 60cm. Find its area

The three sides are set as 5xcm, 12xcm and 13xcm respectively
5x+12x+13x=60
The solution is x = 2
5x=10 12x=24
∵（5x） ²+ （12x） ²= （13x） ²
It is a right triangle, and 5x and 12x are the lengths of the two right sides
The area is 10 × 24/2=120cm ²

It is known that an internal angle of the triangle is 60 °, and the area is 10 ° 3. The perimeter is 20. Find the length of the three sides of the triangle

Let a = 60 °, and the lengths of the three sides are a, B and C respectively,
According to the meaning of the question, s = 1
2bcsinA=
three
4bc=10
3, namely BC = 40 ①,
∵a+b+c=20，
∴a2=b2+c2-2bccosA=b2+c2-bc=（b+c）2-3bc=（20-a）2-120，
Finishing: 40A = 280, i.e. a = 7,
∴b+c=13②，
Simultaneous ① ② solution: B = 5, C = 8; b=8，c=5，
Then the three sides of the triangle are 5, 7 and 8

Q: are two triangles of equal circumference the same size? It's best to explain why it's the same size or different