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Given the chord length 2 of the center angle of 2 radians, what is the arc length of the arc of the center angle?
A = 2 radians = 2 * 180 / pi = 114.592 degrees
R=(L/2)/(SIN(A/2))
=1/(SIN(57.296)
=1.188
C=A*R
=2*1.1884
=2.3768
The arc length of the center angle is 2.3768
Given that the chord length of the center angle with radian number 2 is also 2, the arc length of the center angle is () A. 2 B. 2sin1 C. 2sin-11 D. sin2
As shown in the figure, in the sector OAB, the center angle ∠ AOB = 2, and the point passing through 0 is OC ⊥ AB at point C,
Extend OC, intersect arc AB at point D,
Then ∠ AOD = ∠ BOD = 1, AC = 1
2AB=1，
∵ in RT △ AOC, Ao = AC
sin∠AOC=1
Sin1, radius r = 1
sin1，
‡ arc AB length L= α• r=2•1
sin1=2
sin1=2sin-11．
Therefore: C
Given that the chord length of the center angle of a circle with radian number 2 is 4, the arc length of the center angle is
Given that the chord length of the center angle a with radian number 2 is L = 4, then the arc length of the center angle is C?
The arc radius is r
A = 2 radians = 2 * 180 / pi = 114.5916 degrees
R=(L/2)/SIN(A/2)
=(4/2)/SIN(114.5916/2)
=2/SIN(57.2958)
=2.377
C=A*R=2*2.377=4.754
Given that the chord length of the center angle with radian number 2 is also 2, the arc length of the center angle is () A. 2 B. 2sin1 C. 2sin-11 D. sin2
As shown in the figure, in the sector OAB, the center angle ∠ AOB = 2, and the point passing through 0 is OC ⊥ AB at point C,
Extend OC, intersect arc AB at point D,
Then ∠ AOD = ∠ BOD = 1, AC = 1
2AB=1，
∵ in RT △ AOC, Ao = AC
sin∠AOC=1
Sin1, radius r = 1
sin1，
‡ arc AB length L= α• r=2•1
sin1=2
sin1=2sin-11．
Therefore: C
Given that the chord length of the center angle with radian number 2 is also 2, the arc length of the center angle is () A. 2 B. 2sin1 C. 2sin-11 D. sin2
As shown in the figure, in the sector OAB, the center angle ∠ AOB = 2, and the point passing through 0 is OC ⊥ AB at point C,
Extend OC, intersect arc AB at point D,
Then ∠ AOD = ∠ BOD = 1, AC = 1
2AB=1，
∵ in RT △ AOC, Ao = AC
sin∠AOC=1
Sin1, radius r = 1
sin1，
‡ arc AB length L= α• r=2•1
sin1=2
sin1=2sin-11．
Therefore: C
Given that the chord length of the center angle with radian number 2 is also 2, the arc length of the center angle is () A. 2 B. 2sin1 C. 2sin-11 D. sin2
As shown in the figure, in the sector OAB, the center angle ∠ AOB = 2, and the point passing through 0 is OC ⊥ AB at point C,
Extend OC, intersect arc AB at point D,
Then ∠ AOD = ∠ BOD = 1, AC = 1
2AB=1，
∵ in RT △ AOC, Ao = AC
sin∠AOC=1
Sin1, radius r = 1
sin1，
‡ arc AB length L= α• r=2•1
sin1=2
sin1=2sin-11．
Therefore: C
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