Find the derivative of the curve y = 2 (the third power of x) How to find the derivative of y = 2 (the third power of x)?

Find the derivative of the curve y = 2 (the third power of x) How to find the derivative of y = 2 (the third power of x)?

If you study a little further, you will find that this is the law. When y '= 6x ^ 2 and y = x ^ m, y' = MX ^ (m-1)

Find the derivative of the curve y = f (x) = x to the third power at x = 1

f(x)=x ³
f'(x)=3x ²
f'(1)=3
So f (x) = X ³ The derivative at x = 1 is 3

The derivative of the curve y = 3x to the third power in (1,1) is

y'=(3x^3)'=9x^2
Substitute x = 1
y'=9

Find the second derivative of Y-X (y power of E) = 1

Take the derivative of Y-X * e ^ y = 1, and get y '- e ^ y-xe ^ y * y' = 0, (1-xe ^ y) y '= e ^ y, y' = e ^ y / (1-xe ^ y), (y '' = [e ^ y * y '* (1-xe ^ y) - e ^ y * (- e ^ y-xe ^ y * y')] / (1-xe ^ y) ^ 2 = {y '[e ^ y-xe ^ (2Y) + Xe ^ (2Y)] + e ^ (2Y)} / (1-xe ^ y) ^ 2 = [e ^ (2Y) / (1-xe ^ y) + e ^ (2Y)] / (1-xe ^ y

How to find the derivative of e to the XY power How to find the derivative of this formula? This is just part of an equation Could you please write down the process?

The derivative of X is y * e ^ (XY)
The derivative of Y is x * e ^ (XY)
The partial derivative of X and Y is e ^ (XY) + XY * e ^ (XY)

X power of xy-e + y power of E = 1, find the derivative of Y

xy-e^x+e^y=1
xy-1=e^x-e^y
y+xy'=e^x-y'e^y
y'=(e^x-y)/(x+e^y)