A hexagon can be divided into at least several triangles. How many diagonals can be drawn from one of its vertices? As mentioned in the title

A hexagon can be divided into at least several triangles. How many diagonals can be drawn from one of its vertices? As mentioned in the title

A vertex of an n-polygon can be used as (n-3) diagonal lines and can be divided into (n-2) triangles
A hexagon is a vertex that can be used as four diagonals and divided into five triangles

Starting from a vertex of an n-sided shape, you can lead up to several diagonals, which can divide the polygon into several triangles? Such as the title

Article n-3
N-2

The figure composed of three line segments on different lines is called a triangle. It is called the edge of the triangle, and the vertex of the triangle is called the angle of the triangle

The figure formed by the successive connection of the three line segments on different lines is called a triangle
The line segments that make up a triangle are called the edges of the triangle
The common endpoints of adjacent sides are the vertices of the triangle
The angle formed by two adjacent sides is called the inner angle of a triangle

Triangle vertex, edge, angle

There are three vertices, three edges and three corners

From one vertex of a triangle to the opposite edge______ Is the height of the triangle, and the opposite side is the __

The vertical line from one vertex of a triangle to the opposite edge is the height of the triangle, and the opposite edge is the bottom of the triangle
So the answer is: vertical line, bottom

How many angles does a vertex of a triangle lead a line segment to the opposite side? Is it the flat angle between the vertex and the edge? The problem is not rigorous enough

It's not rigorous enough. It's 8, not 6