Casio calculator Fx-82MS statistical function, variance, average value of the solution Casio's Fx-82MS calculator was discontinued last year Click mode 2 to enter SD mode M + bond acts as DT bond Input data^^^^ Shift + 1 + 3x σ n) "+" = "at this time, the standard deviation is calculated, and the square of (SD mode) is the variance." "" This will not do.

Before mode 2 enters SD mode, clear the last statistics record: shift AC = input data (input one by one, press m + after each data input) multiple identical data are available; input (for example: input 10 2, press 2; 10 m +,; input is shift +,) after inputting data, shift 1 = is average

How to calculate statistical indexes with Casio fx-95es scientific calculator? For example: relative index, weighted average, harmonic average, mode, etc

Weighted average: shfit mode 4 (STAT) 1 (frequency on) mode 2 (STAT) 1 input data in X column = move cursor to freq column, input right, after all data is input, AC shfit 1 (STAT) 4 (VaR) 2 (average) = OK^_ ^!

If α is an acute angle, sin α - cos α = the root two of two, find the value of sin α + cos α

sinα-cosα=(√2)/2
(sinα-cosα)^2=[(√2)/2]^2
(sinα)^2+(cosα)^2-2sinαcosα=1/2
1-2sinαcosα=1/2
2sinαcosα=1/2…………………………………… (1)
(sinα+cosα)^2=(sinα)^2+(cosα)^2+2sinαcosα
(sinα+cosα)^2=1+2sinαcosα
Replace (1) with:
(sinα+cosα)^2=1+(1/2)
(sinα+cosα)^2=3/2
sinα+cosα=±√(3/2)
Considering that α is an acute angle, the negative value is omitted
There are: sin α + cos α = (√ 6) / 2

Given cos (α + π / 6) = - radical 2 / 4, and α is an acute angle, find the value of sin α

From cos (α + π / 6) = - √ 2 / 4 α

2 log log log with 3 as base 2 log log log with 3 as base 32 / 9 log + log log with 3 as base 8 as 2 times as log with 5 as base 3 = what is the logarithm of 3 based on 3?

2log3(2)-log3(32/9)+log3(8)-5*2*log5(3)
=log3(4)-log3(32/9)+log3(8)-5*2*log5(3)
=log3(4/(32/9))+log3(8)-5*2*log5(3)
=log3(4*9/32)+log3(8)-5*2*log5(3)
=log3(9/8)+log3(8)-5*2*log5(3)
=log3((9/8)*8)-5*2*log5(3)
=log3(9)-5*2*log5(3)
=log3(3^2)-10*log5(3)
=2-10*(log(3)/log(5))
=-4.826062

A log of 2 times the logarithm of 2 with 3 as the base - the log of 32 out of 9 with the base of 3 + the logarithm of 8 with the base of 3 - the power of the logarithm of 3 with the base of 5

2log(3)2-log(3)32/9+log(3)8-5^log(5)3
=2log(3)2-log(3)2^5+log(3)9+log(3)2^3-3
=2log(3)2-5log(3)2+log(3)3^2+3log(3)2-3
=2-3
=-1

Log base 8 log 9, log base 3 log 32 is equal to?

log8(9)=2/3log2(3)
log3(32)=5log3(2)
2/3log2(3) * 5log3(2)=10/3

Log base 4 logarithm of 8 log log log base 1 of 9 logarithm of 3 log root 2 logarithm of 4

Log base 4 logarithm of 8 log log log base 1 of 9 logarithm of 3 log root 2 logarithm of 4
＝lg8/lg4-lg3/lg(1/9)-lg4/lg(√2)
＝3lg2/2lg2-lg3/(-2)lg3-2lg2/(1/2)lg2
=3/2 +1/2-4
=-2

If 24 ^ a = 12, log is the logarithm of base 3

a=log（24）12
=1/（log（12）24）
=1/（log（12）12+log（12）2）
=1/（1+1/log（2）12）
=1/（1+1/（2+log（2）3））
Log (2) 3 = (3a-2) / (1-A) is obtained
therefore
log（24）3
=log（24）12-log（24）4
=a-1/（log（2*2）2*2*2*3）
=a-1/（（3/2）+1/（2log（2）3））
=a-2/（3+log（2）3）
=a-2/（3+（（3a-2）/（1-a）））
=3a-2
Log (a) B is the logarithm of B based on a

If 24 ^ a = 12, log is the logarithm of base 2

Log base 24 logarithm of 2 = 1-log logarithm of 12 with base 24
The log is based on 24 and the logarithm of 12 is a
So log is based on 24 and the logarithm of 2 is 1-A