Can logarithm of log 2 base 24 be simplified?

Can logarithm of log 2 base 24 be simplified?

=log2 (8×3)
=log2 8 +log2 3
=3 +log2 3

The logarithm power of 2 with 2 as the base 24 * log the logarithm of 24 with 2 as the base

Loga (n) power of a = n
So the original formula = 24

Let the logarithm of 9 with log base 8 = a, and the logarithm of 5 with log base 3, then LG2=

Log (8,9) = log (3,5) = Ba = LG (9) / LG (8) = 2lg (3) / (3lg (2)) = = > LG (3) = A / (6lg (2)) B = LG (5) / LG (3) = (1-lg (2)) / LG (3) = > LG (3) = > LG (3) = (1-lg (2)) / B if LG (2) = x, then a / (6x) = (1-x) / bab = 6x-x ^ 2x ^ 2-6x + AB = 0 then X1 = (6 + (36-4ab) ^ (1 / 2)) / 2 (2)) / 2 (2)) / 2 (2)) / b let LG (2) = let LG (2) = let LG (6) = (6 + (36-4ab) ^ (1 / 2)) / 2) and= 3 + (9

The logarithm of log base 8 is a, the logarithm of log base 3 is B, and the value of LG2 is calculated

Log base 8 logarithm of 9 = 2 / 3 log logarithm of base 2 3
And then we use the bottom changing formula, there are a bunch of formulas about log

If LG2 = a, Lg3 = B, then log is based on 5, and the logarithm of 12 =? Can (2a + b) / (a + b) be simplified?

log(5)12
=(lg3+lg4)/lg5
=(2lg2+lg3)/(1-lg2)
=(2a+b)/(1-a)

Why is the logarithm of log base 3 x / 3 equal to the logarithm of log base 3 X-1

log3(x/3)=log3(x)-log3(3)=log3(x)-1
The above is based on the arithmetic of logarithm;

Compare the logarithm of 1 + log with x-base 3 and 2log with the logarithm of 2 (x > 0 and X ≠ 1)

1+log3-2log2
=1+lg3/lgx-2lg2/lgx
=(lgx+lg3-lg4)/lgx
=[lg(3x/4)]/lgx,①
x> At 4 / 3, LG (3x / 4) > LG1 = 0, lgx > 0, ① > 0,
00: both
1+log3>2log2;
When x = 4 / 3, 1 + log3 = 2log2;
13<2log2.

Log with 7 / 8 as the base, logarithm of x = 2 / 3, find X

X = (7 / 8) 2 / 3 power = cubic root (7 / 8) square = cubic root 49 / 64 = cubic root 49 / 4

Log base 2 logarithm of 3 xlog log base 27 logarithm of 125 This is a simplification problem

Into a common logarithm
The original formula = (Lg3 / LG2) · (lg125 / lg27)
=(lg3/lg2)·(3lg5/3lg3)
=lg5/lg2
=log₂5

How to calculate the logarithm of 27 based on 9

How many powers of 9 equals 27
The answer is 3 / 2