A practical problem of inequality in grade two To welcome the Universiade and beautify Shenzhen, the garden department decided to use the existing 3490 pots of A-type flowers and 2950 pots of B-type flowers with 50 gardening styles of a and B on both sides of Yingbin Avenue. It is known that 80 pots of A-type flowers and 40 pots of B-type flowers are needed to match a type-A flower, and 50 pots of A-type flowers are required to match a B-type flower, The extracurricular activity group of class 1 of the third grade of a school undertook the design of the horticultural modeling collocation scheme?

Let X be A-shaped and Y-shaped B-shaped
X + y = 50 80x + 50y less than or equal to 3490 40x + 90Y less than or equal to 2950
By solving the equations, X1 = 33, Y1 = 17, X2 = 32, y2 = 18, X3 = 31, Y1 = 19
A: there are three kinds of collocation schemes: the number of a kind of modeling is 33 32 31
The number of types B

Application problems of inequality and inequality group in the second grade of junior high school [detailed steps] 1. Xiaolan plans to use 21 yuan to buy pen and Ben, each pen is 3 yuan, and each book is 2.2 yuan. After he bought 2 brothers, how many pens can he buy? It costs 0.4 yuan to develop a negative film and 0.4 yuan to develop a photo. Everyone gets a photo. The average share of beauty is no more than 0.5 yuan. How many people are there to take a group photo? If each vehicle only carries 4 tons, there will be 20 tons left. If each vehicle only carries 8 tons, the last one is not empty. How many vehicles do you have?

1. If n pens can be bought, the inequality is obtained as follows: (21-2.2 × 2) △ n ≥ 3
The solution is: n ≤ 5.53
Because n must be an integer, n = 5
2. It costs 0. Yuan to make a negative,
3. There are n cars. According to the meaning of the question, we get the inequality: 4N + 20-8 (n-1) < 8
The solution is: n > 5
That is, n = 6

Junior two inequality application problem, urgent! There are 20 workers in a workshop, each of whom can process 5 parts of type A or 4 parts of type B every day. The profit can be 16 yuan for each type a part and 24 yuan for each type B part. Now, the number of people who process type a parts is not less than 2 times of the number of people who process type B parts. When there are more or less people to process parts a, can the maximum profit be made every day?

Let x person process a part. According to the meaning of the question, X ≥ 2 (20-x) can get x ≥ 40 / 3. If the profit is y yuan, then y = 5x × 16 + 4 (20-x) × 24 = 80x + 1920-96x = 1920-16x ∵ - 16

In order to attract people to travel in groups to Tianshui evening scenic spot, Chunqiu travel agency has introduced the following charging standards: if the number of people is less than 25, the per capita tourism cost is 1000 yuan; if the number of people is more than 25, the per capita tourism cost will be reduced by 20 yuan for each additional person. However, the per capita tourism cost shall not be less than 700 yuan, The total fee paid to Chunqiu travel agency is not less than 25000 yuan. Could you tell me the scope of the number of tourists to Tianshui Bay scenic spot this time

If not more than 25
25 * 1000 = 25000 at most
The cost is 25000 yuan for 25 people, which is not less than 25000 yuan
If more than 25 people
Set to x persons
More than x-25
Per capita reduction of 20 (x-25)
It's 1000-20 (x-25) = 1500-20x
But 1500-20x > = 700
So X

Seventh grade mathematics (inequality application) The first, second, third, fourth, fifth and fifth classes of grade seven of a middle school play a single round basketball game in the same group to compete for the right to be qualified. According to the rules of the game, three points will be given for winning one game, one point for one game, and zero point for losing one game. After the group match, the score of class 1 is 9 points. You can figure out how many games class 1 wins and how many loses, If the score of class 4 is 10, can he get out?

∵ five classes play single cycle basketball games,
The competition is only held once every two teams,
There are 4 × 52 = 10 games. Each team plays 4 times with other teams
Set 1 class X win, y level
x+y≤4．
3x+y=9．
Result: x = 3, y = 0, so the record of class 1 is 3 wins, 0 draws and 1 loses
Suppose that the score of class 2 is 10. It is 3 wins, 1 draw and 0 defeat
It can be seen that class 1 was only defeated by class 2. That is to say, class 3, class 4 and class 5 were all defeated by class 1. Class 1 of the three classes was even with class 2 once, and the other two classes were all defeated by class 2
In class 3, class 4 and class 5, the highest points are 2 wins, 1 draw and 1 defeat
So class 1 is out

When someone toured the scenic spot, he took a motorboat to follow the current of SARS, and then went back against the current. The known current speed is 3km / h, and the speed of the motorboat in still water is 18km / h. In order to make the meteor time not more than 3H and not less than 2H, what is the scope of this person?

Let's assume that the range is X
2=2<=x/21+x/15<=3
2<=4x/35<=3
70<=4x<=105
35/2<=x<=105/4

Application of mathematical inequality in Volume 2 of Grade 7 1. For a polygon, except one inner angle, the sum of the other inner angles is 2200 ° and find the number of sides of the polygon and the degree of the inner angle 2. The value of 2x + 3 divided by 3x-6 is positive 3. There are more than 300 and less than 400 trees planted in class A and class A. It is known that one person in class a planted 6 trees, and the others planted 9 trees; one person in class B planted 13 trees, and the others planted 8 trees. The total number of people in class A and class B was calculated Write the process and explain it

1. If (n-2) * 180 = 2200, then n-2 = 12.22222... Take the upper limit, so n-2 = 13, n = 15. From this, we can know that the inner angle is 140 ° and can be 16 polygon, but what you learn is convex polygon, if it is 16 polygon, it is concave polygon! 2, I don't know you have

The second volume of seventh grade mathematics on solving inequality problems How to express the mathematical inequality in the number axis? And about the problem of solution set, I will express the number axis, but I don't know how to express the solution set? List a few questions for my reference. I am in urgent need The exam will be tomorrow. I can't do this kind of questions

1. Solve the inequality
2. Find the solution set position on the drawn axis and mark it
3. If it is within two ranges, the two straight lines should overlap
In a word: first solve the inequality, and then express it on the number axis

About PEP seventh grade mathematics next semester (inequality and inequality group) problem! Fill in the blanks and application questions! Some questions about the unit of "inequality and inequality group" in mathematics of Grade 7 of pep in the next semester include fill in the blank and application questions, mainly application problems! Please be good at this aspect to answer, requirement: 1. Fill in the blanks and write the answers directly; 2. Application problems can be solved by "inequality" or "inequality group" (inequality of one variable degree). Do not use equations or other methods. Unless only in this way can we use equations and other methods. I don't know what to use and what not to use, 3. As long as "set the unknown number", "formula" and "answer" to the problem, the process is not needed, it takes time, and the formula should be correct! 4. Be able to do a few questions, do a few questions, of course, it's the best to do all of them! 5. It will be handed in tomorrow morning, so we'd better finish it before 22 o'clock, 1、 Fill in the blanks 1. The solution set of the univariate linear inequality ax + b greater than 0 (a less than 0) is____ . 2. If x = (a + 3) divided by 2, (a + 2) divided by 3, and X is greater than 2 and greater than y, then the value range of a is_ . 3. If the inequality system X is less than or equal to m + 1 and X is greater than 2m-1, there is no solution_ . 4. A class bought a total of 15 signing pens and ballpoint pens from the cultural goods market, and the amount paid was more than 26 yuan, but less than 27 yuan. It was known that there was no sign pen of 2 yuan, and each ball pen was 1.5 yuan, then the signature pen was purchased___ Branch 2、 Problem solving Zhang Jun left home at 9:50 to catch the 11:00 train. It is known that his home is 10 km away from the railway station. After arriving at the railway station, it takes 20 minutes to enter the station and check in tickets. After leaving home, he walked for 1 km at the speed of 3 km / h, and then went to the railway station by bus? 2. The museum tickets are 10 yuan each. If you buy 30 to 99 tickets at a time, you can get a 20% discount. If you buy more than 100 tickets at a time, you can get a 70% discount. There are 56 students in class A and 54 students in class B (1) If both classes go to the museum together, how much does it cost to buy tickets? (2) If there are more than 30 people and less than 100 people visiting the museum in the two shifts, how many people are required to make it cheaper to buy 100 tickets at a discount of 70% than to buy tickets with a 20% discount for the actual number of people? 3. There are 1530 tons of class a goods and 1150 tons of type B goods to be transported by a certain company in the railway station. Now it is planned to transport these goods to Beijing with 50 pieces of freight cars of type A and type B. It is known that 35 tons of goods of a type and 15 tons of goods of type B can be filled with a section of type B goods, and 25 tons of goods of type A and 35 tons of goods of type B can be filled with a section of type B goods, What are the plans? Please design them

1、 Fill in the blanks
1. X x ＜ - B / a}
2. 4＞a＞1
3. m≥2
4. 8
2、 Problem solving
1. The average travel time of buses is x km / h
1/3+[(10-1)/3]+(20/60)≤(70/60)
x≥18
2. (1) it costs X Yuan,
The most economical way is to buy two shifts together
x≥（56+54）*10*0.7
x≥770
(2) There are two classes with X people in total
100*0.7≤x*0.8
99≥x≥87.5
According to the meaning of the title, there should be at least 88 people
Three

Application problems of mathematical inequality group in junior high school The starting price of a taxi in a city is 10 yuan (10 yuan within 5000 meters). After reaching or exceeding 5 kilometers, the taxi does not drive one kilometer plus 1.2 yuan (less than one kilometer is counted as 1000 meters). Now someone takes a bus from place a to place B, and the fare is 17.2 yuan. How long is the distance from place a to place B? To set, column and procedure

10 x less than 5
Expenses=
10 + 1.2 (X-5) x greater than or equal to 5
So 17.2 = 10 + 1.2 (X-5)
x=11
The distance from a to B is about 11 kilometers

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