In Pascal, how to explain exp (n * ln (x)) to the nth power of X? I don't understand why there is * N in the bracket of exp, what is the meaning of this?

Exp stands for the exponential function with E as the power, for example: exp10 is the 10th power of E; ln is the logarithmic function with E as the base; for example, ln10 is the logarithm of 10 with E as the base;
Exp (n * ln (x)) is the (LN (x)) power of E. if you write this algebraic symbol on the paper, you will understand. In addition, we will tell you that to learn computer well, we must first conquer mathematics!

Compare the size of the fourth power of 27 with the third power of the fourth power of three, and compare the 55th power of 3, the 44th power of 4, and the 33rd power of 5

1. Compare the fourth power of 27 with the third power of 4 of 3
(3^4)^3=(3^3)^4=27^4
therefore
(3^4)^3=27^4
2. Compare the 55th power of 3, the 44th power of 4, and the 33rd power of 5
3^55=(3^5)^11=243^11
The 44th power of 4
4^44=(4^4)^11=256^11
The 33rd power of 5
5^33=(5^3)^11=125^11
125^11＜243^11＜256^11
So:
5^33＜3^55＜4^44

How to compare the 55th power of 2, the 44th power of 3 and the 33rd power of 4

2^55=(2^5)^11
3^44=(3^4)^11
4^33=(4^3)^11
Because 2 ^ 5 < 4 ^ 3 < 3 ^ 4
So the 55th power of 2 < the 33rd power of 4 < the 44th power of 3

Which is the greater of the 55th power of 3 than the 44th power of 4 and the 33rd power of 5 There must be a history

The third power of the fifth power is equal to the fourth power of the fifth power, and the third power of the fifth power is equal to the third power of the fifth power

If sin (π - a) - cos (- a) = 0.5, what is the value of sin cubic (π + a) + cos cubic (2 π - a)

Sin (π - a) - cos (- a) = Sina cosa = 1 / 2, so (Sina COSA) 2 = 1 / 4, i.e. 1-2 sinacosa = 1 / 4, so sinacosa = 3 / 8. The original formula = - sin? A + cos? A = cos? A-SiN? A = (COSA Sina) (COS? 2 + cosasina + sin? A) = - 1 / 2 × (1 + 3)

It is proved that the fourth power of sin a-cos a = the second power of sin - the second power of COS

SIN4a-COS4a=(SIN2a-COS2a)(SIN2a+COS2a)=SIN2a-COS2a
The first step is to use the square difference formula A, the square of B = (a-b) times (a + b)
In the second step, sin2a + cos2a = 1

It is known that sin (3 π + θ) = 1 3, find cos (π + θ) cosθ[cos(π−θ)−1]+cos(θ−2π) sin(θ−3π 2)cos(θ−π)−sin(3π 2 + θ)

∵sin（3π+θ）=-sinθ=1
3，
∴sinθ=-1
3，
The original formula = − cos θ
cosθ(−cosθ−1)+cos(2π−θ)
−sin(3π
2−θ)cos(π−θ)+cosθ
=1
1+cosθ+cosθ
−cos2θ +cosθ=1
1+cosθ+1
1−cosθ=2
1−cos2θ=2
sin2θ=2
(−1
3)2=18．

The fourth power of cos α - the fourth power of sin α

(cosα)^4-(sinα)^4
=[(cosα)^2+(sinα)^2][(cosα)^2-(sinα)^2]
=1*[(cosα)^2-(sinα)^2]
=cos2a

Simplify sin quartic a-cos quartic a I already know how to use the square difference, but then? How did it suddenly become sin square a + cos square a?

(sina)^4-(cosa)^4
=[(sina)^2-(cosa)^2][(sina)^2+(cosa)^2]
=(sina)^2-(cosa)^2
=[1-(cosa)^2]-(cosa)^2
=1-2(cosa)^2

Sin square a + cos fourth power a + sin square ACOS square a =? Last = 1 How

Sin square a + cos fourth power a + sin square ACOS square a
=Sin square a + cos square a (COS square a + sin square a)
=Sin square a + cos square a
=1

In Pascal, how to explain exp (n * ln (x)) to the nth power of X? I don't understand why there is * N in the bracket of exp, what is the meaning of this?