Given that the final edge of angle a passes through point P (m, - 3M). M is not equal to 0, find Sina, cosa, Tana
The square of OP length: M 2 + (- 3 m) 2 = 10 m 2
① When m is a negative number, Op = - M √ 10
In this case, sin α = (- 3M) / (- M √ 10) = (3 / 10) √ 10
cosα=m/(-m√10)=-(√10)/10
tanα=sinα/cosα=3
② When m is a positive number, Op = m √ 10
In this case, sin α = (- 3M) / (m √ 10) = - (3 / 10) √ 10
cosα=m/(m√10)=(√10)/10
tanα=sinα/cosα=-3
Given a point P (- radical 3, y) and Sina = (radical 2 / 4) * y on the final edge of angle a, ask cos a to help,
Sina = Y / radical (3 + y 2) = 2 / 4 under y radical
So 3 + y 2 = 8
y²=5
Cosa = - 3 / 3 (3 + y?) = -- 2 / 4 under 3
If P = (- 2, y) is a point on the final edge of angle A and Sina = - 5 / 5, find cosa I think it's - 2 / 5 times root 5
Ah, I made a mistake. I was confused
From the meaning of the title,
Because the abscissa of a point on the final edge of angle a is negative, it means that the final edge is in the second or third quadrant, and sina is also known to be negative, indicating that the final edge is in the third quadrant
It is known that cosa is negative
According to Sina ^ 2 + cosa ^ 2 = 1
Cosa = - 2 / 5, root 5
Given a point P (radical 3 + 1, y) on the final edge of angle a, and Sina = radical 2 / 2, find y
If there is a definite answer to this question, then the starting edge of angle a is positive x-axis. Since Sina = root 2 / 2, angle a = 45 degrees, so y = radical 3 + 1
If the starting edge of the angle a is not the x-axis and is at the angle B with the x-axis, then y = Tan (45 degrees + b) * (root 3 + 1)
The final edge of the angle a passes through the point P (- radical 3, y), and Sina = (radical 3 / 4) y, and find the values of cosa and Tana
In this case, cosa = x / r = - 3 / 3 (4 √ 3 / 3 / 3) at this time, cosa = x / r = - (4 + 3 / 3 / 3) at this time, cosa = x / r = - 3 / 4 (3 + Y / 3) = (3 + Y / 4) is 3 + Y / 4 = 16 / 3, y = 7 / 3, r = 4 √ 3 / 3 (1) y = √ 21 / 3, at this time, cosa = x / r = - 3 / (4 √ 3 / 3) = - 3 / 4 Tana = Y / x = (, 21 / 3) / (- √ 3) = - √ 7 / 3 (3 / 3 / 3) (- 3 / 3) = - 7 / 3 (3 / 3), 7 / 3 (3 / 3), 7 / and
Given that the coordinates of a point on the final edge of the angle a are p (3, y under the radical) and Sina = Y / 4 of twice the root sign, find Sina and Tana
Given that C = radical 6, ∠ a = 45 degrees, ∠ C = 90 degrees, find B and C
With help, we know that P (- 2, y) is a point on the final edge of the angle A and Sina = (2 * radical (2)) / 5? Because it is not convenient to make root sign, the root sign (2) is root 2 Thank you very much I was a sophomore in high school, and I was confused about mathematics Just explain it
P (- 2, y) is a point on the final edge of angle a, and Sina = (2 * radical (2)) / 5 > 0
So, point P is in the second quadrant, which is Y > 0, cosa
If Sina = - radical 2 / 2, π < a < 3 π / 2, then angle a is equal to As the title
Sina = - radical 2 / 2, π < a < 3 π / 2,
Then the angle a is equal to π + π / 4 = 5 π / 4
If the final edge of angle α coincides with the straight line y = 3x and sin α < 0, then p (m, n) is a point on the final edge of angle α, and | Op|= 10, then m-n=______ .
According to the meaning of the topic
n=3m
m2+n2=10 ,
The results show that M = 1, n = 3, or M = - 1, n = - 3, and sin α < 0,
The final edge of α is in the third quadrant,
∴n<0,
∴m=-1,n=-3,
∴m-n=2.
So the answer is 2
If the final edge of the angle a is on the straight line y = 3x, and P (m, n) is the intersection point of the unit circle, and Sina < 0, then M-N is equal to
If the final edge of the angle a is on the straight line y = 3x, the intersection point P (m, n) with the unit circle, and Sina < 0
m<0,n<0
n=3m
m²+n²=1
10m²=1
m²=1/10
m=-√10/10
n=-3√10/10
m-n=-√10/10+3√10/10=√10/5