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The third power of the root a divided by the root AB times the root B fraction a
Original formula = √ [(B / a) △ ab × (a 3 / b)]
=√(a/b)
=√(ab/b²)
=√ab)/√b²
=√ab)/|b|
-B 2 * the fifth power of root AB * (3 / 2 * the third power B of root a) / 3 root a fraction B Urgent ah, speed solution, thank you!
- b / 2 × a b ⁵ × （2 / 3 × √ a b ³ ）/ 3√（b / a）
= - a b ⁶ / 2 × 2 / 3 × b √ a b / 3 √（a b / a ²）
= - a b ⁷ √ a b / （9 √ a b / a）
= - a ² b ⁷ / 9
2 times the root 3 divided by 1.5 to the third power and 12 to the sixth power =?
2 times the root 3 divided by 1.5 to the third power and 12 to the sixth power
=2 root sign 3 △ third root sign 1.5 * six root sign 12
=2 * six root sign 3 ^ 3 △ sixth root sign (1 / 1.5 ^ 2) * sixth root sign 12
=2 * sixth root (27 / 2.25 * 12)
=2 * six Radix 144
=2 * triple root 12
"Question supplement: the answer is 6"
If the answer is 6, you have to multiply the original form to get:
2 times the root 3 "times" is 1.5 to the third power and 12 to the sixth power
=2 root 3 * three times root 1.5 * 6 times root 12
=2 root 3 * 6 times root 1.5 ^ 2 * 6 times root 12
=2 roots 3 * 6 times roots 27
=2 root sign 3 * 6 times root sign 3 ^ 3
=2 root sign 3 * root sign 3 = 6
The fifth power of 16A + the fourth power of 32A under the radical Reduction to the simplest quadratic radical
√(16a^5+32a^4)
=√[16a^4(a+2)]
=4a²√(a+2)
The third power of root 16A + the second power of 32A (a > 0)
3 / 8 of 4 times root sign = √ 6
The square of √ + a of √ + a = a
The - 1 power of 2 + the cube of root 4 minus the cube of root 8 + the power of (root 2) 0
=-12 √ 4 √ is the root sign
When a = root 2, B = cube root 2, find the value of (1) the square of a - (minus) the cube of B (2) the sixth power of a-b That help to calculate, 5555, I am very anxious! Will add wealth!
(1) a² - b³
= (√2)² - (³√2)³
= 2 - 2
= 0
(2) a^6 - b^6
= (a²)³ - (b³)²
= 2³ - 2²
= 8 - 4
= 4
If x If x
Under radical sign (X-2) 2 + | 4-x|
=|x-2|+|4-x|
=2-x+4-x
=6-2x
When x ＜ 0, the absolute value (x 2 - x under the root sign) is equal to
|√x²-x|
=| |x|-x|
=|-x-x|
=|-2x|
=-2x
When x + 2 < 0 is known, the absolute value of 1-radical (1 + x) 2 is reduced
x+2<0
x+1<-1
|1-radical (1 + x) 2 | = | 1 - (- x-1) | = | x + 2 | = - X-2
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