Simplify root sign [16 + 2 (1 + root 5) (1 + 2 and root 3)]

Simplify root sign [16 + 2 (1 + root 5) (1 + 2 and root 3)]

√[16+2(1+√5)(1+2√3)]
=√(18+4√3+2√5+4√15)
=√[1+4√3+2√5+12+4√15+5]
=√[1+4√3+2√5+(2√3)²+2(2√3)(√5)+(√5)²]
=√[1+2(2√3+√5)+(2√3+√5)²]
=√[(1+2√3+√5)²]
=1+2√3+√5

Root 16 divided by root 2 =?

Double root 2

How to simplify Radix 16

Root 16 = under root sign ((plus or minus 4) square) = plus or minus 4

Simplify (Radix 6 + Radix 3 + 2 + Radix 2) divided by (2 Radix 2 + Radix 3 + 1)

(root 6 + root 3 + 2 + root 2) divided by (2 root 2 + root 3 + 1) = [root 3 * (root 2 + 1) + root 2 * (root 2 + 1)] / (2 root 2 + 3 + 1) = (root 3 + root 2) * (root 2 + 1) / [(root 3 + root 2) + (root 2 + 1)] = 1 / [1 / (root 2 + 1) + 1 / (root 3 + root 2)...] = (root 3 + root 2) = (root 3 + root 2) = (root 3 + root 2) = (root 3 + root 2) + 1 / (root 3 + root 2)

Simplification: 2 root sign 3 + root sign 6-3 root sign 2 divided by 2 + root sign 2-root 6

2 root 3 + root 6-3 root 2 divided by 2 + root 2-root 6
=2√3-√2/3;
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Simplify 5sinxcosx-5 times root 3 cos ^ 2x + 5 times root 3 divided by 2

The original formula = 5 / 2 * sin2x-5 √ 3 (1 + cos2x) / 2 + 5 √ 3 / 2
=5*(sin2x*1/2-cos2x*√3/2)-5√3/2+5√3/2
=5(sin2xcosπ/3-cos2xsinπ/3)
=5sin(2x-π/3)

Calculate the root number 18 divided by the root 8 times the root 2 / 27 A 2 / 3 / 6 B 1 / 6 C 4 9 / 6 D 18 root number 6 Choose which one, write a process, do not adopt the process of HA``

√18/√8=3/2
√(27/2)=3/2 √6
Multiply the two: 9 / 4 √ 6
Answer c

How to calculate these three problems: (1) root 24 divided by root 3 - root 6 × 1 / 3 (2) (root 3 + 1) (root 3-1) How to calculate these three problems: (1) root 24 divided by root 3 - root 6 × 1 / 3 (2) (root 3 + 1) (root 3-1) / root 5 (2 + root 5) - 1 (3) solve the equation (x-3) square - 25 = 0

(1)√24/√3-√6*√(1/3)=√8-√2=√2
(2)(√3+1)(√3-1)/√5(2+√5)-1=2(√5-2)√5/5-1=1-4√5/5
(3) (x-3) ^ 2-25 = (x-3 + 5) (x-3-5) = (X-2) (X-8) = 0, get X1 = 2, X2 = 8

Calculation: 3 times the root 20 divided by (3 times 4 times the root 2 and 2 3 times), 5 times the root 6 times the root 27 divided by (- 13 times the root 26) I have just come into contact with these contents, such as ideas

(1) = 3 * root 20 / (3 / 4 * root 8 / 3)
=(root 3 * 3 * 20) / (root 3 / 4 * 3 / 4 * 8 / 3)
=Root 180 / root 3 / 2
=Radical 120
=2 * radical 30
(2) = (5 * radical (27 * 6)) / - radical (13 * 26)
=45 root number 2 / - 13 root number 2
=-45/13

The result of calculating the root 3 divided by [1 / 3 of the root plus 1 / 2 of the root] is

(√3)÷[1/(√3)]+1/(√2)]
=(√3)÷[(√3)/3+(√2)/2]
=(√3)÷[(2√3+3√2)/6]
=(√3)×[6/(2√3+3√2)]
=(√3)×[6(2√3-3√2)/(-6)]
=(√3)×(3√2-2√3)
=3(√6)-6