Given the real number a.b.c.d.m, if a and B are opposite to each other, C.D are reciprocal, and the absolute value of M is 2, find the square root of a + B divided into the square root of M + m and the square root of CD

Given the real number a.b.c.d.m, if a and B are opposite to each other, C.D are reciprocal, and the absolute value of M is 2, find the square root of a + B divided into the square root of M + m and the square root of CD

There is a problem with the topic!
Given that a and B are opposite numbers to each other, then a + B = 0
——Therefore, it is meaningless to use √ (a + b) as the denominator in the title!

It is known that a and B are opposite numbers to each other, C and D are reciprocal to each other, and the absolute value of M is root two. Find the flat of a + CD + B + M

a+cd+b+m²
=0+1+2
=3

If the absolute value X-1 and the radical 2Y + 1 are opposite to each other, find the value of X / y The more detailed the better,

Opposite numbers
So | X-1 | + √ (2Y + 1) = 0
Make the equation true
Each is equal to 0
x=1 y=-1/2
So x / y = - 2

Root [X-2] + radical [2-x] + absolute value [2y-1] = 5, find x.y

Radical [X-2] + radical [2-x] + absolute value [2y-1] = 5
Radical [X-2] → [X-2] ≥ 0, → x ≥ 2
Radical [2-x] → [2-x] ≥ 0, → x ≤ 2
ν x = 2, radical [X-2] + Radix [2-x] = 0 + 0 = 0
The absolute value [2y-1] = 5, [2y-1] = ± 5, → y = - 2 or y = 3
/ / x = 2, y = - 2 or y = 3

If the absolute values of x-2y + 9 and X + 3 under the root sign are opposite to each other, then x =? Y =?

If one is greater than 0, the other is less than 0
So both are equal to zero
So x-2y + 9 = 0
x+3=0
x=-3
y=(x+9)/2=3

If the graph of the first order function y = MX + n is shown in the figure, then the result of simplifying the algebraic expression | m + n | - | M-N |, is______ .

According to the properties of the first order function, M > 0, n > 0, that is, M + n > 0;
When x = - 1, y < 0, that is - M + n < 0,
∴m-n＞0．
So | m + n | - | M-N | = m + n - (m-n) = 2n

If the graph of the first order function y = - MX + n passes through the second, third and fourth quadrant, the square of √ [M-N] and the absolute value of N are equal to A..B.-M .C.2M-N D.M-2N

∵ the graph of the function y = - MX + n passes through the second, third and fourth quadrant

The graph of the first order function y = MX + n passes through one, two and four quadrants as shown in the figure. Try to simplify the algebraic formula: √ m ^ 2 - √ n ^ 2 - | M-N |

The image of the first order function y = MX + n passes through the first, second and fourth quadrants
Then M < 0, n > 0
√m^2-√n^2-|m-n|.=-M-N-(-M+N)=-2N

Given that the image of the first order function y = MX + n of X is shown in the figure, then | N-M | radical n | can be reduced to | 1,3,4 quadrants

If we know that the image of the first order function y = MX + n of X passes through the first three or four quadrants, then there are:
m>0,n

Let P (x, y) be a moving point on the image of the function y = x squared-1 (x is greater than the root 3), and M = (x-1 / 3x + Y-5) + (Y-2 / x + 3y-7), then the coordinates of P can be obtained when m is the smallest

A:
y=x^2-1
m=(3x+y-5)/(x-1)+(x+3y-7)/(y-2)
=(3x+x^2-1-5)/(x-1)+(x+3x^2-3-7)/(x^2-1-2)
=(x^2+3x-6)/(x-1)+(3x^2+x-10)/(x^2-3)
m'(x)=(2x+3)/(x-1)-(x^2+3x-6)/(x-1)^2+(6x+1)/(x^2-3)-(6x^3+2x^2-20x)/(x^2-3)^2
=(x^2-2x+3)[1/(x-1)^2-1/(x^2-3)^2]
=(x^2-2x+3)(x^2+x-4)(x^2-x-2)/[(x-1)^2*(x^2-3)^2]
Because x > √ 3, only x ^ 2-x-2 may have a value of 0
Let m '(x) = 0, then: x ^ 2-x-2 = 0, the solution is: x = 2 (x = - 1 does not conform to rounding off)
So:
When √ 3 = 0, m (x) is an increasing function
So: when x = 2, m gets the minimum value of 8
Substituting x = 2 into the parabolic equation y = x ^ 2-1 yields y = 3
So the coordinates of point P are (2,3)