Why is the second power of minus half equal to the root two? The definition written in the textbook is y = a x power (a > 0) minus half is not less than zero

Why is the second power of minus half equal to the root two? The definition written in the textbook is y = a x power (a > 0) minus half is not less than zero

It should be: one half of the minus one-half power equals the root two
It may be wrong to read or write
(1 / 2) ^ (- 1 / 2) = (1 / 2) ^ [(- 1) * (1 / 2)] = 2 ^ (1 / 2) = radical two

Is x equal to the second power of X under the radical?

Two thirds of X is equal to three identical numbers multiplied to the square of X

What is the half power of the root two

1 / 4 power of 2

If B = (radical A-4) + (Radix 4-A) - half, then the b-th power of a =?

It is known that B = (radical A-4) + (Radix 4-A) - half
Desire makes radical meaningful
Then A-4 ≥ 0 and 4-A ≥ 0 should be satisfied
So a = 4
So B = 0 + 0-1 / 2 = - 1 / 2
So a ^ B = 4 ^ (- 1 / 2) = 1 / 4 ^ (1 / 2) = 1 / 2
If you don't understand, I wish you a happy study!

How to simplify the third power of radical a? It's a mistake. It's the third power of the root minus a

First, write the root sign a to the second power of a, and then multiply the power by 3, that is, a is the third power of a, and then simplify the root sign a of a times

The square of 1 / 2 × (root 3-1) + root 2-1 + root 3 - (root 2 of 2) is negative to the first power

1/2(√3-1)²+1/(√2-1)+√3-(√2/2)^-1
=1/2(4-2√3)+√2+1+√3-√2
=2-√3+1+√3
=3

Simplification: 48th of the third power of the square root m square n

The third power of Mn is 48n

How to simplify m square times n fourth power + m fourth power times n square under root sign M ≥ 0, n ≥ 0

(M 2)
=|mn|√(m²+n²)
=mn√(m²+n²)

The fifth power of AB under 2 parts of B is multiplied by (- a cube B under 3 / 2 roots) divided by B of part a under 3 roots 2 / b times the root [a (the fifth power of B)] times [- 3 / 2 times the root (the third power of a) b)] divided by 3 roots (B / a)

2 / b times the root sign [a (the fifth power of B)] times [- 3 / 2 times the root (the third power of a) b)] divided by 3 radical (B / a) = (2 / b) × √ (AB ^ 5) × (- 3 / 2 × √ (a 3 b)) / 3 √ (B / a) = (- 1 / b) × √ (AB ^ 5 × a 3 B × A / b) = (- 1 / b) × a ·

What's the square of five times the third fifths of five divided by the root five times the seventh tenth power of five

Title: [5 ^ 2 * 5 ^ (3 / 5)] / [5 ^ (1 / 2) * 5 ^ (7 / 10)] =?
The original formula = 5 ^ 2 * 5 ^ (3 / 5) * 5 ^ (- 1 / 2) * 5 ^ (- 7 / 10)
=5^[(2+3/5)-(1/2+7/10)].
=5^(13/5-12/10).
=5^[(26-12)/10].
=5^(14/10).
=5^(7/5)
The original formula = 5 ^ (1 + 2 / 5)
The original formula = 5 * 5 ^ (2 / 5)
In other words, the original formula = 5 times the 2nd power of 5