It is known that the minimum integer solution of inequality 5 (X-2) + 8 < 6 (x-1) = 7 is the solution of the equation 2x AX = 3 on X, and the value of formula 4a-1 is obtained that. The question is wrong. It should be: known that the minimum integer solution of inequality 5 (X-2) + 8 < 6 (x-1) + 7 is the solution of the equation 2x AX = 3 about X, and find the value of formula 4a-1

5（x-2）+8＜6（x-1）+7
5x-2

The integer solution of 2x + 31 / 2 (x-3) is the root of the equation 2X-4 = ax about X. find the value of A Good points to earn!

2x+3<1
2x<-2
x<-1
X>0
x>1/2(x-3)
x>1/2x-2/3
1/2x>-2/3
x>-3
So: - 3 so: x = - 2
Replace x = - 2 into 2X-4 = ax
-4-4=-2a
-8=-2a
A=4

Given that the solution of equation 2x-ax = 3 is the smallest integer solution of 5 [X-2] - 7 〈 6 [X-1] - 8, find the value of the integral formula 4a-14 △ a

Inequality
5x-10-7

Equation ax-6 = 2x, can you find out the relationship between the solution X of the equation and the value of a? When a goes to what kind of integer, the solution of the equation is a positive integer, and find out this

The equation ax-6 = 2x is sorted into (A-2) x = 6. Here, the unknown coefficient is discussed. When a = 2, the equation has no solution; when a ≠ 2, the coefficient is converted to 1, and x = 6 / (A-2), which is the solution of the original equation

The minimum integer solution of 6 (x-1) + 7 > 5 (X-2) + 8 is the solution of the equation 2x AX = 3. Find the value of A

Solving inequality: 6x-6 + 7 > 5x-10 + 8
x>-3
Its minimum integer solution is x = - 2
Substituting it into the equation, 2 * (- 2) - A * (- 2) = 3
-4+2a=3
a=3.5

If the solution of the equation AX = 2x + 2 about X is an integer, find the integer a

solve equations:
Ax = 2x + 2
Ax-2x = 2, merge
(A-2) x = 2, coefficient 1
x=2/(a-2)
∵ the solution is an integer
/ / A-2 = 1, or A-2 = 2, A-2 = - 1, A-2 = - 2
∴a1=3,a2=4 ,a3=1,a4=0

The equation 2x + m / x-3 = - 1 of X has no solution. Find the value of M

2x+m/x-3=-1
De denominator 2x + M = 3-x
3x=3-m
x=(3-m)/3
From (3-m) / 3 = 3, M = - 6

On the equation x-3 3-2x + 3-x 2 + MX = - 1 has no solution, find the value of M

∵ the equation x-3-2x + 3-x 2 + MX = - 1 has no solution
∴x=3
3-2x of x-3 + 2 of 3-x + MX = - 1
(3-2x)/(x-3)+(2+mx)/(3-x)=-1
(3-2x)/(x-3)-(2+mx)/(x-3)=-1
3-2x-2-mx=-x+3
3-2x-2-mx+x-3=0
-x-mx=2
-3-3m=2
-3m=5
m=-5/3

When x = - M = - 3

The equation is 2x + m / x-3 = - 1
Think x is not equal to 3
Solving the equation 2x + M = - x + 3
x=3-m/3
X is not equal to 3 3-m / 3! = 3
M is not equal to - 6
In other words, when m = - 6, there is no solution to the equation x-3 of 2x + M = - 1

If the equation x + 1 / 2x-x ^ 2 + X / M = 2x-1, when m is the value, the equation has no solution

2X / (x + 1) - M / (x? 2 + x) = (2x-1) / X both sides of the equation are multiplied by the simplest common denominator (x? + x)
2x²-m=(2x-1)(x+1)
2x²-m=2x²+x-1
x=1-m
When x 2 + x = 0, the equation has augmented roots x = 0 and x = - 1
When x = 0, 1-m = 0, M = 1
When x = - 1, 1-m = - 1, M = 2
Therefore, when m = 1 or M = 2, the equation has no solution