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X + 2Z = 3; 2x + y = 2; 2Y + Z = 7 to solve the ternary system of linear equations by substitution method! X + 2Z = 3; 2x + y = 2; 2Y + Z = 7 to solve the ternary system of linear equations by substitution method!
x＋2z＝3 (1); 2x＋y＝2 (2) ; 2y＋z＝7 (3)
From (1) x = 3-2z (4). (4) into (2), 6-4z + y = 2 is obtained, and y = 4z-4, (5) is obtained
(5) By substituting (3), we get 8z-8 + Z = 7, and the solution is Z = 5 / 3, x = - 1 / 3, y = 8 / 3
How to solve the equations X: Y: z = 1:2:3 2x-y + Z = 9!
Let x = k, y = 2K, z = 3K
2k-2k+3k=9
3k=9
K=3
x=k=3
y=2k=2*3=6
z=3k=3*3=9
The process of solving the system of equations x squared + 2XY + y squared = 1 and 2x squared - y = 2 process
X ^ 2 + 2XY + y ^ 2 = (1 + 2x) ^ 2-y = 2, is the equation like this?
Solving the equations 2xy-5 √ (XY + 1) = 10 x ^ 2 + y ^ 2 = 34
(2) 2 (XY + 1) - 5 √ (XY + 1) = 12 = = > 2 (x + 1) - 5 √ (XY + 1) = 12 = = > 2 (XY + 1) - 5 √ (XY + 1) - 12 = 0 = = > [2 √ (XY + 1) + 3] [(XY + 1) - 4] = 0 (decomposed by cross multiplication) = = = > (XY + 1) - 4 = 0 (∵ 2 √ (x + 1) + 3 > 0) = = = > (x + 1) = 4 ∨ (x + 1) = 4 ∨ x ∧ (1) \\\\\\\\\\\\+ y ^ 2 + 2XY = 64 =
1 / 2x + 3Y = - 6 1 / 2x + y = 2 bivariate linear equation, calculated by addition and subtraction method!
[reference answer]
(1/2)x+3y=-6 ①
(1/2)x+y=2 ②
① - 2
(1/2)x+3y-(1/2)x-y=-6-2
2y=-8
y=-4
By introducing y = - 4 into (2), the
x=[2-(-4)]×2=12
The solution of the original equations is x = 12, y = - 4
In the bivariate equation 2x-3y = 10, when x = 2, what is y = and when y = - 2, x = how much
X=2 Y=-2
Y=-2 X=2
Who can help me calculate the following problems? The bivariate linear equation 2x-6 + y = 7 2x + y = 1 x + 2Y = 5 x-2y = 7 2x-3y = 5 x = y = 15 2x-4y=6 3x-2y=5
2x-6+y=7 y=13-2x
2x+y=1 y=1-2x
x+2y=5 x=5-2y
x-2y=7 x=7+2y
2x-3y=5 x=(5+3y)/2
x+y=15 x=15-y
2x-4y=6 x=3+2y
3x-2y=5 x=(5+2y)/3
Find the solution of bivariate linear equation x + y = 4,2x + 3Y = 10 If you want to use, you have to replace it
X + y = 4 x + 2Y = 8
If x + 3Y = 10 and 2x + 2Y = 8 are subtracted by y = 2, then x + y = 4 is taken to get x = 2
The solution of bivariate linear equation x + y = 53y-2x = - 10
X=5-Y
Then: 3y-2 * (5-y) = - 10
3Y-10+2Y=-10
5Y=0
Y=0
X=5-0=5
Solving equations X / 7 = Y / 10, 2x + 3Y = 44
By X / 7 = Y / 10
X = (7 / 10) y
Dai Ren 2x + 3Y = 44
The results show that y = 10; X = 7
RELATED INFORMATIONS
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- 2. To solve the equations 2x−3y＝10 −4x+y＝−5
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