To solve the equations 2x−3y＝10 −4x+y＝−5

To solve the equations 2x−3y＝10 −4x+y＝−5

2x−3y＝10①
−4x+y＝−5② ，
From - 4x + y = - 5 to y = 4x-5,
Substituting y = 4x-5 into ①, x = 1
2．
Substituting in 2, we get - 4 × 1
2+y=-5，
y=-3．
The solution of the original equations is
x＝1
Two
y＝−3 ．

If the square of (x + Y-5) and y-2x + 10 | are opposite numbers to each other, then what is x and what is y?

In general, for any rational number a, its opposite number is - A. A itself can be either a positive number, a negative number, or zero

If the square of (a + 3) and | B-1 | are opposite numbers to each other, and the solution of the equation a + X / 4-3y = 1 / 2x + B of X is x = - 1, find the square - 3 of 2Y

The solution consists of the square of (a + 3) and | B-1 |
That is, a + 3 = 0 and B-1 = 0
That is, a = - 3, B = 1
Therefore, the equation a X / 4-3y = 1 / 2x + B
It is (- 3) x / 4-3y = 1 / 2x + 1
The solution of equation a X / 4-3y = 1 / 2x + B is x = - 1
That is - 3 + (- 1) / 4-3y = 1 / 2 (- 1) + 1
That is - 3-3 / 4 = 3Y
That is 3Y = - 15 / 4
That is y = - 5 / 4
So the square of 2Y is - 3
=2（-5/4）^2-3
=25/8-3
=1/8

Simplify the square of 1 / 7 (- 2x + 3Y) (- 2x-3y) - 10 (x + y)

1/7(4x^2-9y^2)-10x-10y=1/7*4X^2-1/7*9Y^2-10X-10Y

If the squares of | x-2y + 3 | and (2x + 3y-10) are opposite to each other, find the values of X and y

If one of them is greater than 0, the other is less than 0. Therefore, both of them are equal to 0. Therefore, x-2y + 3 = 0 (1) 2x + 3y-10 = 0 (2) * 3 + (2) * 23x + 9 + 4x-20 = 0 = 11 / 7Y = (10-2x

The absolute value of (4x + 3y-1) quadratic + 2x-y + 7 is known

The absolute value of (4x + 3y-1) + 2x-y + 7

Given that the solutions of the system of equations [2x + 5Y = - 6, mx-ny = - 4} and {3x-5y = 16, NX + my = - 8} have the same solution, find the value of the 2008 square of (2m + n) I'm dying

First, by combining 2x + 5Y = - 6 and 3x-5y = 16, we can get x = 2, y = - 2
If we take it into mx-ny = - 4, NX + my = - 8, we can get m = 1, n = - 3
2m+2n=1
Is the 2008 power of 1 or 1

It is known that the solutions of (LL) 3x + y = 8,2x-y = 7 and (LL) x + NY = m, MX + y = n are the same for the system of equations (LL) 3x + y = 8,2x-y = 7, and find the values of M, n

From the first set of equations can be solved x = 3, y = - 1, and then x, y into the second set of equations can be solved to solve M = 1, n = 2!

Xiao Ming and Xiao Hua solve the equation system {MX + y = 5, (1) 2x NY = 13 (2). Xiao Ming misunderstood m and solved {x = 7 / 2, y = - 2, Xiao Hua misread n, The solution is {x = 3, y = - 7. Do you know the correct solution of the original equations?

In the equation system {MX + y = 5, (1) 2x-ny = 13 (2), the solution is {M = 2, n = 3, n = 3 {x = 3, y = - 7, into the equation system {MX + y = 5, (1) 2x-ny = 13 (2), get the solution {M = 4, n = 1, Xiaoming read wrong m, Xiaohua wrong n, then correct m, n = 3, put into the equation group {MX + y = 3, (1) 2x + y = 3, (1) 2x-ny = 5, (1) 2x-ny = 5, (1) 2x-ny = 13 (2), get the solution {M = 4, n = 3, put into the equation system {MX + y = 5, (1) 2x-ny = 13 (2)

At the same time, a and B solve the equations {MX + y = 5 {2x NY = 13. A misunderstands m and gets x = 3.5 y = - 2. B misreads N and solves x = 3, y = - 7 The equation group {m y = 5 {2x-ny=13

From the meaning of the title: x = 2 / 7, y = - 2 is the solution of the equation 2x NY = 13, we can get: 7 + 2n = 13, n = 3, x = 3, y = 7 is the solution of the equation MX + y = 5 (1) 2x-3y=13…… (2) (1) × 3 + (2) is: 4x = 28 x = 2. Substituting x = 2 into (1) gives: y = -