If the solutions of {4x-3y = 1 and MX + (m-2) y = 10 are equal, then M =? Come on,

4x-3y=1,mx+(m-2)y=10
The values of the solutions are equal, so x = y
So 4x-3x = x = 1 = y
∴m+(m-2)=10
M = 6
What do you not understand

If the solutions of the system of equations 4x-3y = 1 MX + (m-2) y = 10 are equal, then M =?

The values are equal,
That is, y = X
Substituting 4x-3y = 1
4X-3X=1
X=1,Y=1
Substituting MX + (m-2) y = 10
M+M-2=10
2M=12
M=6

If the solution X and y of the equation system {4x + 3Y = 1, MX + (1-m) y = 3 are opposite numbers to each other, then the value of M is?

That is, y = - X
Substituting 4x + 3Y = 1
4x-3x=1
X=1
y=-1
So m -- (1-m) = 3
m-1+m=3
M=2

Binary system of first order equations 4x+3y＝7 For KX + (K − 1) y = 3, the values of solution X and y are equal

According to the meaning of the title, x = y,
Ψ 4x + 3Y = 7 can be changed into 4x + 3x = 7,
∴x=1，y=1．
Substituting x = 1, y = 1 into KX + (k-1) y = 3, we can get the following results:
k+k-1=3，
∴k=2

Binary system of first order equations 4x−3y＝1 In the solution of KX + (K − 1) y = 3, if the values of X and y are equal, then K=______ .

From the meaning of the title: y = x,
Substituting it into the equations, we can get the following results
4x−3x＝1
kx+(k−1)x＝3 ，
The solution is: x = 1, k = 2,
Then k = 2
So the answer is: 2

On the system of bivariate linear equations of X and Y 2x−y＝1 When MX + 3Y = 2 has no solution, the value of M is () A. -6 B. 6 C. 1 D. 0

2x−y＝1①
mx+3y＝2② ，
From ①, y = 2x-1 ③,
Substituting ③ into ②, MX + 6x-3 = 2,
That is (M + 6) x = 5,
∵ there is no solution to the equations,
∴m=-6．
So choose a

If the system of quadratic equations with respect to x, y ax+3y=9 If 2x-y = 1 has no solution, then a =___ .

ax+3y=9①
2x-y=1② ，
From ②, y = 2x-1 ③,
③ Substituting ①, ax + 3 (2x-1) = 1,
That is (a + 6) x = 4,
∵ there is no solution to the equations,
∴a+6=0，
∴a=-6．
So the answer is: - 6

Given that the equation mx-3y = 2x-1 is a system of bivariate first-order equations about X and y, then M satisfies the condition () A .m ≠2 B .m ≠1 C .m ≠0 D .m ≠ -2

It is known that the equation mx-3y = 2x-1 is a system of bivariate first-order equations on X, y
(m-2)x-3y+1=0:
m -2≠0
That is, m ≠ 2

If the values of X and y are equal in the solutions of the binary system of first order equations 2x-3y = - 2 and MX + (M + 2) y = 4, then what is m equal to?

Because x = y
So 2x-3y = 2x-3x = - 2
X=2
mx+(m+2)y=(2m+2)x=4
(2m+2)×2=4
2m+2=2
So m = 0

If MX + 3Y = 9 2x + y = 3 has innumerable solutions, then M = () A m=9 B m=6 C m=-6 D m=-9

B m=6

If the solutions of {4x-3y = 1 and MX + (m-2) y = 10 are equal, then M =? Come on,