Multiplication formula: (1) [(x + 2) (X-2)] 2 (2) (2x-y-3) 2 Factorization factor: (1) (the fourth power of 5 * the third power of 3 - the third power of 5 * 5? * 3)

Multiplication formula: (1) [(x + 2) (X-2)] 2 (2) (2x-y-3) 2 Factorization factor: (1) (the fourth power of 5 * the third power of 3 - the third power of 5 * 5? * 3)

1）[(X+2)(X-2)]2
=(x²-2)²
=x^4-2x²+4
(2)（2x-y-3)²
=(2x-y)²-6(2x-y)+9
=4x²-4xy+y²-12x+6y+9
(1) (the fourth power of 5 * the third power of 3 - the third power of 5 * 5? * 3)
=The fourth power of 5 * 3 (3? - 5)
=625*3*4
=2500*3
=7500

Using the multiplication formula to calculate: （1）（x-2）（x4+16）（x+2）（x2+4）； （2）（2a-3b-1）（1+3b-2a）．

（1）（x-2）（x4+16）（x+2）（x2+4），
=（x-2）（x+2）（x2+4）（x4+16），
=（x2-4）（x2+4）（x4+16），
=（x4-16）（x4+16），
=x8-256；
（2）（2a-3b-1）（1+3b-2a），
=-（2a-3b-1）2，
=-4a2-9b2+12ab+4a-6b-1．

Use the multiplication formula to calculate (2x + 3Y) ^ 2-2 (2x + 3) (3x-2) + (3x-2) ^ 2

(2x+3y)^2-2(2x+3)(3x-2)+(3x-2)^2
=(2X+3Y-3X+2)^2
=(3Y-X+2)^2

(2x + 3) × (3x-2) is calculated by multiplication formula In fact, the original question is (x + y) (2x + y) - (x + 2Y) (x-2y)

It can be written as: 2x (3x-2) + 3 (3x-2) to get 6x? - 4x + 9x-6 = 6x + 5x-6

Qin Jiushao algorithm for polynomial: F (x) = 7x ^ 7 + 6x ^ 6 + 5x ^ 5 + 4x ^ 4 + 3x ^ 3 + 2x ^ 2 + x = 3

f(x)=((((((7x+6)x+5)x+4)x+3)x+2)x+1)x=21324
7 6 5 4 3 2 1 0
x=3 7*3=21 21+6=27 27*3+5=86 86*3+4=262 262*3+3=789 789*3+2=2369 2369*3+1=7108 7108*3=21324
If you can't make a table, you can arrange it yourself. The principle is at the top. Making a table is to arrange the coefficients of all items of X in a row, that is, 7, 6, 5, 4, 3, 2, 1, 0 (constant coefficient is 0), and then according to the following calculation method, the result is 21324

In the process of calculating the polynomial f (x) = 5x5 + 4x4 + 3x3 + 2x2 + X + 1 with "qinjiushao algorithm", when x = 2, it is necessary to go through______ Sum of multiplication operations______ Second addition operation

The polynomial f (x) = 5x5 + 4x4 + 3x3 + 2x2 + X + 1 = ((((5x + 4) x + 3) x + 2) x + 1) x + 1 is not difficult to find that it needs five times of multiplication and five times of addition
So the answer is: 5, 5

Using Qin Jiushao algorithm to calculate the polynomial f (x) = 3x6 + 4x5 + 5X4 + 6x3 + 7X2 + 8x + 1, when x = 4, the times of multiplication and addition are () A. 66 B. 56 C. 55 D. 65

f（x）=3x6+4x5+5x4+6x3+7x2+8x+1
=（（（（（3x+4）x+5）x+6）x+7）x+8）x+1，
When x = 4, the times of multiplication and addition are 6 and 6, respectively
Therefore, a

The value of X for equation 2x (x-1) - x (2x-5) = 12 is______ .

By removing the brackets, we can get: 2x2-2x-2x2 + 5x = 12,
By combining the similar items, 3x = 12,
When the coefficient is changed to 1, x = 4
Therefore, fill in 4

Find the value of the unknown number suitable for the equation 3x (2x-3) - (4-2x) x = (4x-1) 2x

3x(2x-3)-(4-2x)x=(4x-1)2x
6x²-9x-4x+2x²=8x²-2x
-7x=-2x
5x=0
X=0

If the unknown number is X., then 2x + 3 = 7. Find X

x=2.