Given that the angle α is an acute angle and sin2 α - sin α cos α - 2cos α = 0, find the value of Tan α Sorry, here sin2 α is the square of sin α, 2cos α, because it should be 2 times the square of cos α

Given that the angle α is an acute angle and sin2 α - sin α cos α - 2cos α = 0, find the value of Tan α Sorry, here sin2 α is the square of sin α, 2cos α, because it should be 2 times the square of cos α

sin2α-sinαcosα-2cosα=0
2sinαcosα-sinαcosα-2cosα=0
sinαcosα-2cosα=0
(sinα-2)cosα=0
Cos α = 0 or sin α = 2 (round off, - 1

Let f (x) = cos (2x-3) + sin ^ 2-cos ^ 2x (1) find the minimum positive period of function f (x). 2. Find the range of G (x) Urgent need

The function f (x) = cos (2x - π / 3) + sin ^ 2 x-cos ^ 2 x
=cos2xcos(π/3)+sin2xsin(π/3)-cos2x
=√3/2 sin2x-1/2 cos2x
=sin(2x-π/6)
The minimum positive period T = π of function f (x)
The value range of G (x)?

What is the value range of the function y = sin ^ 2x + SiN x cos x? （0 1L sorry Your answer is not in the options Thank you.

(0, (1 + root2) / 2]

Find the value range of the function y cos ^ 2x-sin ^ x-4sinx + 1, X ∈ R

Let t = SiNx with | t|

Given the function y = (SiN x + cos x) (SiN x + cos x) + 2cos x * cos x, find its decreasing interval Friendly tone and friendly attitude

According to the equation, y = 1 + 2sinxcosx + 2 (cosx) ^ 2
Using the formula of decreasing power and double angle, y = sin2x + cos2x + 2 is obtained
Then, using the auxiliary angle formula, y = radical 2 * sin (2x + π / 4) + 2
Therefore, when 2x + π / 4 belongs to [2K π + π / 2,2k π + 3 π / 2], and K is an integer, y is monotonically reduced,
So x belongs to [K π + π / 8, K π + 5 / 8], and K is an integer
So the decreasing interval of Y is [K π + π / 8, K π + 5 / 8], and K is an integer

Given the function y = (sin χ + cos χ) 2 + 2cos χ (1), find its decreasing interval and (2) find its maximum value

The derivation of y = (sin χ + cos χ) 2 + 2cos? χ shows that y '= 2 (SiNx + cosx) (cosx SiNx) - 4cosxsinx = 2 (COS? X-sin? X) - 2sin2x = 2cos2x-2sin2x = 2 √ 2 [√ 2 / 2cos2x - √ 2 / 2sin2x] = 2 √ 2 (cos2xcos π / 4-sin2xsin π / 4) = 2 √ 2cos (2x +...)

The function f (x) = 2 √ 3sinxcosx-2cos (x + π / 4) cos (x - π / 4) is known, To find the minimum positive period and symmetric axis equation of function FX Find the value range of function FX on the interval [- π / 12, π / 2]

f(x)=2√3sinxcosx-2cos(x+π/4)cos(x-π/4)
=√3sin2x+2sin(x+π/4-π/2)cos(x-π/4)
=√3sin2x+sin(2x-π/2)
=√3sin2x-cos2x
=2sin(2x-π/6)
T=2π/2=π
2X - π / 6 = π / 2 + K π, K is an integer
The axis of symmetry x = π / 3 + K / 2 π, where k is an integer
x∈【-π/12,π/2】
2x-π/6∈[-π/3,5/6π]
F (x) belongs to [- √ 3,2]
Hope to adopt

If the minimum positive period of the function y = cos ^ 2wx sin ^ 2wx (W > 0) is u, then what is the monotone increasing interval of the function y = 2Sin (Wx + Wu / 4)?

If y = cos ^ 2 (Wx) - Sin ^ 2 (Wx) = cos (2wx), the minimum positive period is 2 π / 2W = π, then w = 1, then the function y = 2Sin (Wx + π / 4) = 2Sin (x + π / 4), and the monotone interval is - π / 2
Homework help users 2017-09-20
report

Given the function f (x) = cos (2x - π / 3) + 2Sin (x - π / 4) sin (x + π / 4), find the value range of function f (x) on the interval [0, π / 2]

f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4) f(x)=1/2cos 2x+√3/2sin 2x+2(sin x-cos x)(xin x+cos x) =1/2cos 2x+√3/2sin

Let f (x) = 4cos (ω X - π / 6) sin ω x-cos (2 ω x + π), where ω > 0, (1) find the value range of function y = f (x)

F (x) = 4cos (ω X - π / 6) Sinn - ω X - cos (2 ω x + π) = 4 (cosswxcos π / 6 + sinwxsin π 6) sinwx + cos2wx = 2 √ 3sinwxcoswx + 2Sin + 2sin2wx + cos2wx + cos2wx = √ 3sin2wx + 1-cos2wx + cos2wx + cos2wx = √ 3sin2wx + 1, the maximum value of 1 + √ 3, the minimum value of 1 - √ 3, the minimum value of 1 - √ 3, function y = f (x) value domain [1...It's a good idea