Reduction of 7 divided by radical 7

Reduction of 7 divided by radical 7

Solution 7 / √ 7 = 7 √ 7 / 7 = √ 7

Simplification: (1-A) × Radix 1 divided by (- 1-A)

Root 1 = 1
(1-a)=-(a-1)
(-1-a)=-(a+1)
So:: (1-A) × root 1 divided by (- 1-A) = (a + 1) of (A-1)

Find the reduced 5 root sign a divided by four times root sign B

5 of 4B √ ab

If b > a > 0, reduce the square of root (a-b) (the square is in the root) divided by the root a-radical B, and the result is?

|A-B | / √ a - √ B, because B is greater than a, | A-B | = B-A = (√ B - √ a) * (√ B + √ a) | A-B | / √ a - √ B = (√ B - √ a) * (√ B + √ a) / √ a - √ B = - (√ B + √ a)

Let m be The integer part of 5, n is 5, try to find the value of m-n

∵4＜5＜9，
∴2＜
5＜3，
Qi
The integral part and decimal part of 5 are 2 respectively,
5-2，
∴m=2，n=
5-2，
∴m-n=2-
5+2=4-
5．

Given that the integer part of root 5-8 is m and the decimal part is n, find the value of 1 / 3m-5n

Because 4 < 5 < 16
SO 2 < 5 < 4
-6<√5 -8<-4
So the integer part of root 5-8 is equal to - 5
That is, M = - 5, so n = root 5-8 - (- 5) = root 5-3
3m-5n = 3 * (- 5) - 5 * (root 5-3) = - 5 root number 5
So 1 / (3m-5n) = - 1 / 5 root number 5 = - (root number 5) / 25

Known: 3m-5n = 0, find the value of M / (M + n) + m / (m-n) - m ^ 2 / (m ^ 2-N ^ 2)

Merge polynomial, (M / M + n) + (M / m-n) - (m ^ 2 / m ^ 2-N ^ 2)
=2m^2/(m^2-n^2)-(m^2/m^2-n^2)
=m^2/(m^2-n^2)
Substituting M = 5N / 3 into the equation, (5N / 3) ^ 2 / [(5N / 3) ^ 2-N ^ 2] = (25 / 9) / [(25 / 9) - 1] = 25 / 16

Given m < 0, reduce 2n radical M / n To process

2n radical M / n
=-2√mn

Given m < 0, simplify 2n radical (M / N) + 2m radical (n / M)

Because, m < 0
If the root sign (M / N) and root sign (n / M) are meaningful, then n

Simplify and evaluate (M + 2n) ^ 2 - (m-n) (M + 3n), where M = radical 2 and N = radical 3

21 + 2 root sign 6