If the final edge of the angle a passes through (- 3,4), then cos 2A =? Sin 2A =? Tan 2A =?

If the final edge of the angle a passes through (- 3,4), then cos 2A =? Sin 2A =? Tan 2A =?

If the final edge of the angle α crosses the point (- 3,4), then: x = - 3, y = 4, then: r = 5, thus: sin α = Y / r = 4 / 5cos α = x / r = - 3 / 5tan α = Y / x = - 4 / 3, then: Cos2 α = 2cos 2 α - 1 = - 7 / 25sin α = 2Sin α = - 24 / 25tan2 α = (2tan α) / (1-tan 2 α), or tan2 α = sin

Given that sin a = 5 / 13 and a is the angle of the first quadrant, find sin 2a, cos 2A

A is the first quadrant angle and a is an acute angle
cos²a=1-sin²a=1-25/168=144/169
cosa=12/13
sin2a=2sinacosa=2×5/13×12/13=120/169
cos2a=cos²a-sin²a=144/169-25/169=119/169

The point P (a, - 2A) is a point on the final edge of angle θ, where a > 0. Find sin θ cos θ It's best to have a formula I'm stupid

The distance from P to the origin d = √ 5A,
cosθ=x/d=a/√5a=1/√5
sinθ=y/d=-2a/√5a=-2/√5
So sin θ cos θ = (1 / √ 5) * (- 2 / √ 5) = - 2 / 5
Also, don't belittle yourself, these topics will do more, everyone's intelligence is similar, to believe in yourself

Let the coordinates of a point P on the final edge of angle α be (COS π) 5，sinπ 5) Then α is equal to () A. π Five B. -π Five C. 2kπ+3 10π（k∈Z） D. 2kπ+π 5（k∈Z）

∵cosα=cosπ
5，sinα=sinπ
5，
ν α is and π
5 angles with the same end edges,
∴α=2kπ+π
5（k∈Z），
Therefore, D

Let the coordinates of a point P on the final edge of angle α be (COS π) 5，sinπ 5) Then α is equal to () A. π Five B. -π Five C. 2kπ+3 10π（k∈Z） D. 2kπ+π 5（k∈Z）

∵cosα=cosπ
5，sinα=sinπ
5，
ν α is and π
5 angles with the same end edges,
∴α=2kπ+π
5（k∈Z），
Therefore, D

Given that the coordinates of a point P on the final edge of angle α are (sin θ, - cos θ), what is sin α equal to? Ask for detailed process, do not understand, can I ask?

The coordinates of a point P on the final edge of angle α are (sin θ, - cos θ),
x=sinθ,y=-cosθ
r=√[sin²θ+(-cosθ)²]=1
According to the definition of trigonometric function
∴sinα=y/r=-cosθ
I don't know how to ask questions,

If P (sin Θ, cos Θ) is a point on the final edge of angle a, then the value of a is equal to D. K + W / 2 - Θ Why?

Tan α = cot θ = Tan (U / 2 - θ)
So α = k Θ + Θ, K ∈ Z

If cos (θ / 2) = 3 / 5, sin (θ / 2) = - 4 / 5, which line does the final edge of angle θ fall on?

sinθ/2=3/5>1/2
2kπ+π/6<θ/2<2kπ+5π/6
4kπ+π/3<θ<4kπ+5π/3
cosθ/2=-4/5<-√2/2
2kπ+3π/4<θ/2<2kπ+5π/4
4kπ+3π/2<θ<4kπ+5π/2
therefore
4kπ+3π/2<θ<4kπ+5π/3
So in the fourth quadrant

If cos θ 2＝3 5，sinθ 2＝4 5, then the final edge of angle θ falls on the straight line () A. 24x-7y=0 B. 24x+7y=0 C. 7x+24y=0 D. 7x-24y=0

tan（θ
2）=4
3，
tanθ=2×4
Three
1−(4
3)2=-24
7，
Is the slope of the straight line,
Therefore, B

Given that there is a point m (3, m) on the final edge of the angle θ, and sin θ + cos θ = - 1 / 5, find M

M number 1 or 4 thank you
sin+cos<0
So the fourth quadrant
sin<0,cos>0
Because sin? 2 + cos? 2 = 1
sin+cos=-1/5
So sin = - 4 / 5, cos = 3 / 5
cos=3/√(3²+m²)=3/5
m²=16
Delta Quadrant
m=-4