How to use the number axis to express the fifth quarter of the root?
1. First, draw a right angle side, and cut off one or two length units on the right angle side, and the intercept points are a and B points;
2. The length of connecting point a and B is √ 5, and then bisecting line AB is √ 5 / 2
How to express Radix 5 on number axis
Make a vertical line through X = 2, cut a line with length of 1 on the vertical line, connect the origin and the point, according to the Pythagorean theorem, the length of the line is the root 5, and then cut the root 5 on the number axis with the origin as the center
The number axis represents 5 / 4 of the root How to express 5 / 4 on a number axis? It's a root! A root! A 5 / 4! Not a 5 / 4!
"Mirage flying star"
On the X and Y axes, take points a and B with a ratio of 1:1 / 2 respectively, and the values of AB and ab are √ (5 / 4)
For example, point a (1, 0), point B (0, 1 / 2)
AB²=1²+(1/2)²=1+1/4=5/4
AB=√(5/4)
You're right. Good bye
According to the Pythagorean theorem, the points expressed as root 3 and root 5 are respectively drawn on the number axis
You first draw a number axis, take the origin as P, and make a vertical line y passing through point P, so that points 1, 2, 3 and 4 are ABCD respectively. Use a compass to intercept PA '= PA on the vertical line y, connect AA', and then intercept PB '= AA' = root sign on the vertical line y. 2. Connect ab ', and ab' = root 3. Similarly, you can intercept PC '= ab' on the vertical line y, and then connect BC ', and then BC' = root number, Then you can draw the root 3 and root 5 on the number axis
I hope you can follow my train of thought
(2 times root 40 minus 3 times root 27) divide by root 6
4√10-9√2/2
4.2 the absolute value of the root sign 2 minus 3 times the absolute value of the root sign 2 times the root sign 2 divided by one third of the root sign
Because 4.2 < 3 times root number 2,
So the absolute value of root number 2 of 4.2 minus 3 times is equal to 3 times of root number 2 minus 4.2,
The following "divided by one third of the root" is equal to multiplying by the root 3,
So this part of the subtraction is 3 times the root 2,
This will result in - 4.2
1: Root six divided by root twenty-seven times root fifty-two: root three minus root six difference times root six two-thirds 3: dispatch minus five 1: Root six divided by root twenty-seven times root fifty 2: The difference between the root three minus the root six times the root six plus two-thirds of the root 3: The zero power of subtraction five minus two minus the absolute value of root seven plus one-third of the minus second minus root seven
10 / 3,
What is the value of arccos 〔 (Radix 6-radix 2) / 4] (accurate to 0.0001)
Cos150 degree = 2 (cos75) ^ 2-1 = - √ 3 / 2
(cos75)^2=(2-√3)/4=(8-4√3)/16
=(6-2√12-2)/16
=(√6-√2)^2/16
cos75〉0
So cos75 = (√ 6 - √ 2) / 4
So arccos (√ 6 - √ 2) / 4 = 5 π / 12 = 1.3090
What angle is Tan radical 2:2-
It's about 35 degrees and 16 minutes
Calculate Tan [(1 / 2) arccos (- 2 root sign 6 / 5)] -2 radical 6 is a molecule
Let a = arccos (- 2 * 6 ^ (1 / 2) / 5)
cosa=-2*6^(1/2)/5,sina=1/5
tg(a/2)=(1-cosa)/sina
=(1+2*6^(1/2)/5)*5
=5+2*6^(1/2)