When x = 4, y = 1 / 9, find the value of X * (1 / x under the root) - (4Y under the root) - 1 * (the third power of Y under the root)
x=4,y=1/9
So √ x = 2
√y=1/3
Original formula = 4 * (1 / 2) - 2 / 3-9 * y √ y
=2-2/3-1/3
=1
(the square of X + 4xy + the square of 4Y to the third power of y-4y) × (x-2y is 4xy + x), where x = root 2-1, y = root 2 + 1
The original formula = y (x + 2Y) (x-2y) / (x + 2Y) 2 × (4xy + X? - 2XY) / (x-2y)
=y(x+2y)(x-2y)/(x+2y)²×x(x+2y)/(x-2y)
=xy
When x = √ 2-1, y = √ 2 + 1,
The original formula = (√ 2-1) (√ 2 + 1) = 2-1 = 1
Reduce the fraction of root sign (x-2y) (X Cubic - 4x square y + 4Y square x)
If it is, the original formula = radical {(x-2y) fraction [x (x-2xy + 4Y Square)]} = root sign {(x-2y) fraction [x (x-2y) square]} = root sign [x (x-2y)]
When x = 4, y = 9 / 1, find the third power of X radical X / 1-radical 4y-y / 1 radical y
x=4,y=1/9
So √ x = 2
√y=1/3
Original formula = 4 * (1 / 2) - 2 / 3-9 * y √ y
=2-2/3-1/3
=1
How to simplify the 4x power of 4Y under the four fifths root sign 4 / 5 (√ 3x / 4Y cubic)
4 / 5 (√ 3x / 4Y cubic)
=(2 lxl√3y)/5y²
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Find the following values: root 1 and 9 / 16 - root 144 + root 81
=5/4-12+9
=-7/4
9 / 16 + 144 + 81 =?
√9/16+√144+√81
=√(3/4)^2+√12^2+√9^2
=3/4+12+9
=21 and 3 / 4
=87/4
81 times 125 under the radical
81 times 125 under the radical
=Nine out of twelve times 125
=Three quarters times 125
=375 in 4
=93 and 3 / 4
Root number 0.25 × 144 0.01 × 81
Root number 0.25 × 144 0.01 × 81
=(0.5x12) (0.1x9)
=3/20
Is 9 / 16 of the root = 4 followed by 12, right?
incorrect,
√(9/16)=3/4.