Find the definition domain of X-1 under the function f (x) = LG (x + 2) / radical

Find the definition domain of X-1 under the function f (x) = LG (x + 2) / radical

x> 1 or - 2

Function f (x) = the domain of 1-1gx under radical

1-lgx>=0
X>0
The solution
Zero

If cos (x - π / 4) = radical two / 10, X ∈ (π / 2, 3 π / 4), then TaNx=_____

sinx=sin[(x-π/4)+π/4]=sin(x-π/4)cos(π/4)+cos(x-π/4)sinx=4/5
∴cosx=-3/5,tanx=-4/3

Function y = - 2Sin (AX + 1) - 1, (a)

A = - 2 hope it works

If the function y = ax ^ 3 / 3-ax ^ 2 / 2-2ax (a ≠ 0) is an increasing function on the interval (- 1,2), find the value range of A

The derivative function = ax ^ 2-ax-2a is greater than or equal to 0 on (- 1,2)
=If a (x + 1) (X-2) is greater than or equal to 0, it always holds on (- 1,2)
Because a ≠ 0, a

Given that the minimum positive period of the function y = 2Sin (AX + π / 5) is π / 2, then a=

T = 2 π / A, so a = 4

The minimum positive period of the function y = 2Sin (x / 3-x / 4) + 1 is___ With what knowledge

y=2sin(x/3-x/4)+1=y=2sin(x/12)+1,
Then the minimum positive period is 2 π / (1 / 12) = 24 π
Period = 2 π / W

Given the function FX = 2Sin (2x + 3), find the minimum positive period and the minimum direct union of the function y = FX, and find the minimum or maximum conditions of X Finding monotone decreasing interval of function FX in interval [0, Pai]

f(x)=2sin(2x+π/3)
Minimum positive period: 2 π / ω = 2 π / 2 = π
Minimum: F (x) = 2 * (- 1) = - 2
Maximum value: F (x) = 2 * 1 = 2
When sin (2x + π / 3) = - 1, the minimum value is obtained;
2x+π/3=2kπ-π/2
x=(kπ-5π/12)
When sin (2x + π / 3) = 1, the maximum value is obtained;
2x+π/3=2kπ+π/2
x=(kπ-π/12)
Monotone decreasing interval:
π/2≤2x+π/3≤π
π/12≤x≤π/3

Known function y = 1 2sinx+π If the minimum positive period of a (a > 0) is 3 π, then a=______ .

From the periodic formula t = 2 π
ω shows that t = 2 π
One
A=3π，
A = 3
Two
So the answer is three
Two

The minimum positive period of the function y = 2sin2x-1 is______ .

y=2sin2x-1=-（1-2sin2x）=1-cos2x，
∵ω=2，∴T=π．
So the answer is: π