The value range of the function f (x) = (2 to the power of X + 1) is?

The value range of the function f (x) = (2 to the power of X + 1) is?

The second power of x > 0
The x power of 2 + 1 > 1
Zero

Given the function f (x) = 10 to the x power + 10 to the - x power of 10 to the - x power of - 10, and to find the value range

It is easy to know that the definition domain of the function f (x) = [10 ^ X-10 ^ (- x)] / [10 ^ x + 10 ^ (- x)]. Is R. substitution. Let t = 10 ^ x.x ∈ R, ν T > 0. Therefore, the problem can be reduced to finding the value range of function g (T) = [T - (1 / T)] / [T + (1 / T)] on (0, + ∞), ∵ t (T) - 1 = - 2 / (t ᙽ 1) ? t ﹥ 0. = = = > 0 ﹤ 1 / (t ﹤ 1) ∵ 1. = = > 0 ﹤ 2 / (t ﹤ 1) = = > 0 ﹤ 1-g (T) ﹤ 2. = = > 0 ﹤ 1-g (T) ? t ﹤ 0. = = > t ﹤ t ? 0. ｛ 0. =

If the value range of the function f (x) = x to the power of X + X + 1 is r, then the value range of function g (x) = x to the power of X + ax + 1 is r

If f (x) is r, a = 0
g(x)=x^2+1≥1
The value range of G (x) is: [1, + ∞)

The value range of the function y = (10x + 10-x) / (10x-10-x) is x power and - x power of 10

y/1=(10^x+10^-x)/(10^x-10^-x)
The formula of sum fraction ratio is: (y + 1) / Y-1) = 10 ^ (2x) > 0
(y+1)(y-1)>0
y> 1 or Y

Y = 2 x power minus 1 / 2 x power minus 2 to find the definition domain and value domain

The original formula = 1 - 1 / (2 ^ x-1) because 2 ^ X - 1 is the denominator, 2 ^ X-1 is not equal to zero, and X is not equal to 0
The definition field is that x is not equal to 0
The range of values is divided into several situations, and I discuss them slowly, but the result is not (1,2)

The value range of y = 2 to the power of X-1

1/ (x-1)≠0
So y ≠ 2 ^ 0 = 1
And the exponential function is greater than 0
So the range (0,1) ∪ (1, + ∞)

Please tell me how to get the value range of y = 3 minus one by one

3 to the negative x-th power, greater than 0 is not equal to 1
The negative x-th power of 3-1 is greater than - 1 and is not equal to 0
So the value range greater than - 1 is not equal to 0

What is the value range of the function y = e to the x power plus 1 / 1 of e to the x power and minus 1

Let a = e ^ X
Then a > 0
y=(a-1)/(a+1)
=(a+1-2)/(a+1)
=1-2/(a+1)
a+1>1
0<1/(a+1)<1
-2<-2/(a+1)<0
-1<1-2/(a+1)<1
Range (- 1,1)

The value range of y = 1 / 2 power of X?

Solution by y = x ^ (1 / 2)
Know x ≥ 0
That is, x ^ (1 / 2) ≥ 0
That is, y ≥ 0
Therefore, the value range of the function is [0, positive infinity)

What is the range of y = 2 to the power of X and X ≤ 1?

（0,2］