If the real number x and y satisfy 2x-4xy + 4y-6x + 9 = 0, then 8y under x times root sign=

If the real number x and y satisfy 2x-4xy + 4y-6x + 9 = 0, then 8y under x times root sign=

2x-4xy + 4y-6x + 9 = 0
(x^2-4xy+4y^2)+(x^2-6x+9)=0
(x-2y)^2+(x-3)^2=0
So we have x-2y = 0, x-3 = 0
That is, x = 3, y = x / 2 = 3 / 2
X * radical 8y = 3 radical (8 * 3 / 2) = 3 radical 12 = 3 * 2 radical 3 = 6 radical 3
When 2x-y / 2x + 2Y + X + y = 3, find the 値 of the algebraic formula 2x-y / 2x + 2Y + X + Y / 6x-3y
2x-y\x+y=3
2x-y=3(x+y)
2x-y=3x+3y
3x-2x=-y-3y
x=-4y
2x-y/2x+2y+x+y/6x-3y
=(-8y-y)/(-8y+2y)+(-4y+y)/(-24y-3y)
=3/2+1/9
=29/18
Find the monotone interval of function f (x) = x ^ 3-4x ^ 2 + 5x + 1
Using derivative solution to find the detailed solution 0
f（x）=x^3-4x^2+5x+1
Derivation
f'(x)=3x²-8x+5
=(3x-5) (x-1) > 0
x> 5 / 3 or X
If one root of the quadratic equation (m-1) x with respect to X is zero, then the value of M is zero
Let x = 0, the equation be M & # 178; - 1 = 0, the solution be m = - 1 or M = 1 (rounding off)
Given that the real number XY satisfies the formula | 2x + 5Y + 5 | + | 2y-2 | = 0, find the value of X + 2Y
fast
2x+5y+5=0
2y-2=0
The solution is x = - 5, y = 1
If the value of 4x square - 2x + 5 is 7, how much is 2x square - x + 1?
The value of 4x squared - 2x + 5 is 7
4x²-2x+5=7
4x²-2x=2
2x²-x=1
2X square - x + 1 = 1 + 1 = 2
Because 4x & sup2; - 2x + 5 = 7
So (4x & sup2; - 2x + 5) × 1 / 2 = 7 × 1 / 2
2x²-x+5/2=7/2
So 2x & sup2; - x = 7 / 2-5 / 2 = 1
So:
2x²-x+1=1+1=2
4x²-2x+5=7
4x²-2x=2
2x²-x=1
2x²-x-1=1-1=0
Given the function f (x) = 3x times + 4x times, and the function g (x) = 5x times, try to judge the number and coordinates of the common points of the two function images
If one root of the quadratic equation x & # 178; - (m-1) x + M = 0 is - 1, and the other root is -
x=-1
So 1 + (m-1) + M = 0
M=0
By Weida theorem
x1x2=m=0
So the other one follows x = 0
Substituting x = - 1 into the original equation.
1＋m－1＋m＝0
m＝0
The original equation is: X & # 178; + x = 0
x﹙x＋1﹚＝0
x1＝﹣1
X20
The other root is: x = 0
In the entanglement, the known set M = {x | a + 1 ≤ x ≤ 2A + 1}, n = {x | X & # 178; - 3x ≤ 0}
【1】 If a = 3, find m ∩ n
[2] If M is a subset of N, find the value range of real number a
I went to Baidu online and said the second question is that the range of a is from negative infinity to 2. My answer on the exam paper is a < 0 or 0 ≤ a ≤ 2. Is this wrong,
Sorry, wrong number. Set n is X & # 178; - 3x ≤ 10
The range of a is negative infinity to 2, and a < 0 or 0 ≤ a ≤ 2
Is the same answer, but you separate, nondescript, prevent the teacher misjudgment
Given x2 + 2x = 3, find the value of the algebraic formula X4 + 7X3 + 8x2-13x + 15
∵x2+2x=3，∴x4+7x3+8x2-13x+15=（x2+2x）2+3x（x2+2x）-2（x2+2x）-9x+15=9+9x-6-9x+15=18．